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<h3>Cool Down (5 minutes)</h3>
<h4>Student Activity</h4>
<p>Here is the function \(f\) for Clare’s moldy bread that you saw earlier.</p>
<table class="os-raise-midsizetable">
<thead>
<tr>
<th scope="col"> \(d\), time since mold spotting (days)</th>
<th scope="col">\(f(d)\), area covered by mold (square millimeters)</th>
</tr>
</thead>
<tbody>
<tr>
<td>
0
</td>
<td>
1
</td>
</tr>
<tr>
<td>
1
</td>
<td>
2
</td>
</tr>
<tr>
<td>
2
</td>
<td>
4
</td>
</tr>
<tr>
<td>
3
</td>
<td>
8
</td>
</tr>
<tr>
<td>
4
</td>
<td>
16
</td>
</tr>
<tr>
<td>
5
</td>
<td>
32
</td>
</tr>
<tr>
<td>
6
</td>
<td>
64
</td>
</tr>
</tbody>
</table>
<br>
<ol class="os-raise-noindent">
<li> What is the average rate of change for the mold over the 6 days? <br>
<br>
<strong>Answer:</strong> 10.5 square millimeters per day: \(\frac{f(6)−f(0)}{6−0}=10.5\)
</li>
<li> How well does the average rate of change describe how the mold changes for these 6 days? <br>
<br>
<strong>Answer:</strong> The average rate of change does not accurately describe how the mold changes over the 6-day
period. The first day it only grows by 1 square millimeter, while on the fifth day it grows by 32 square
millimeters.
</li>
<li> How could the average rate of change be more accurate? <br>
<br>
<strong>Answer:</strong> The domain used to find the average rate of change could be smaller. The average rate of
change of different intervals could be compared.
</li>
</ol>
<h4>Response to Student Thinking</h4>
<h5>More Chances</h5>
<p>Students will have more opportunities to understand the mathematical ideas in this cool-down, so there is no need to
slow down or add additional work to the next lessons. Instead, use the results of this cool-down to provide guidance
for what to look for and emphasize over the next several lessons to support students in advancing their current
understanding.</p>