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75197e86-86f0-4c77-b9bb-980710e0106e.html
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<p><strong><em>Students will complete the following questions to practice the skills they have learned in this lesson.</em></strong></p>
<p>For questions 1–3, factor.</p>
<ol class="os-raise-noindent">
<li>\(u^2 − 9u + 18\)
</ol>
<ul>
<li>\((u + 9)(u + 2)\)</li>
<li>\((u − 3)(u − 6)\)</li>
<li>\((u + 3)(u + 6)\)</li>
<li>\((u + 3)(u − 6)\)</li>
</ul>
</li>
</ol>
<p><strong>Answer: </strong> \((u − 3)(u − 6)\)</p>
<ol class="os-raise-noindent" start="2">
<li>\(8 − 6x + x^2\)
</ol>
<ul>
<li>\((x + 4)(x + 2)\)</li>
<li>\((x − 8)(x + 1)\)</li>
<li>\((x − 4)(x − 2)\)</li>
<li>\((x + 4)(x − 2)\)</li>
</ul>
</li>
</ol>
<p><strong>Answer:</strong> \((x − 4)(x − 2)\)</p>
<ol class="os-raise-noindent" start="3">
<li>\(a^2 + 5ab − 24b^2\)
</ol>
<ul>
<li>\((a − 8b)(a + 3b)\) </li>
<li>\((a − 8b)(a − 3b)\) </li>
<li>\((a + 8b)(a + 3b)\) </li>
<li>\((a + 8b)(a − 3b)\) </li>
</ul>
</li>
</ol>
<p><strong>Answer: </strong> \((a + 8b)(a − 3b)\) </p>
<p>For questions 4–5, factor using the trial and error method.</p>
<ol class="os-raise-noindent" start="4">
<li>\( 4b^2 + 5b + 1\)
</ol>
<ul>
<li>\((b − 1)(4b − 1)\)</li>
<li> \((5b + 1)(b − 1)\)</li>
<li>\((5b + 1)(b + 1)\)</li>
<li>\((b + 1)(4b + 1)\)</li>
</ul>
</li>
</ol>
<p><strong>Answer: </strong>\((b + 1)(4b + 1)\)</p>
<ol class="os-raise-noindent" start="5">
<li>\(30x^2 − 53xy − 21y^2\)
</ol>
<ul>
<li>\((3x + y)(10x − 21y)\)</li>
<li>\((15x + y)(2x − 21y)\)</li>
<li>\((5x + y)(6x − 21y)\)</li>
<li>\((3x − y)(10x − 21y)\)</li>
</ul>
</li>
</ol>
<p><strong>Answer: </strong>\((3x + y)(10x − 21y)\)</p>
<ol class="os-raise-noindent" start="6">
<li>Factor completely using the “\(ac\)” method: \(4y^2 + 8y + 3\).
</ol>
<ul>
<li>\((2y − 1)(2y − 3)\)</li>
<li>\((2y + 1)(2y + 3)\)</li>
<li>\((2y − 1)(2y + 3)\)</li>
<li>\((2y + 1)(2y − 3)\)</li>
</ul>
</li>
</ol>
<p><strong>Answer:</strong> \((2y + 1)(2y + 3)\)</p>
<ol class="os-raise-noindent" start="7">
<li>Factor completely using the “\(ac\)” method: \(18w^2 − 39w + 18\).
</ol>
<ul>
<li> \((9w − 2)(2w − 3)\) </li>
<li>\( 3(3w − 2)(2w − 3)\) </li>
<li> \(3(3w + 2)(2w + 3)\) </li>
<li> \(3(3w + 2)(2w − 3)\) </li>
</ul>
</li>
</ol>
<p><strong>Answer: </strong>\( 3(3w − 2)(2w − 3)\) </p>
<ol class="os-raise-noindent" start="8">
<li>Factor by substitution: \(h^4 + 4h^2 − 12\).
</ol>
<ul>
<li> \((h^2 + 2)(h^2 − 6)\)</li>
<li> \((h − 2)(h + 6)\)</li>
<li> \((h + 2)(h − 6)\)</li>
<li> \((h^2 − 2)(h^2 + 6)\)</li>
</ul>
</li>
</ol>
<p><strong>Answer:</strong> \((h^2 − 2)(h^2 + 6)\)</p>
<ol class="os-raise-noindent" start="9">
<li>Factor by substitution: \((y − 4)^2 + 8(y − 4) + 15\).
</ol>
<ul>
<li>\((y + 1)^2\) </li>
<li>\((y + 5)(y + 3)\)</li>
<li>\((y − 1)(y + 1)\)</li>
<li>\((y − 5)(y − 3)\)</li>
</ul>
</li>
</ol>
<p><strong>Answer:</strong> \((y − 1)(y + 1)\)</p>
<ol class="os-raise-noindent" start="10">
<li>Factor using any method: \(13z^2 + 39z − 26\).</ol>
<ul>
<li>\(13(2z + 1)(z + 2)\)</li>
<li>\(13(2z − 1)(z + 2)\)</li>
<li>\(13(2z + 1)(z − 2)\)</li>
<li>\(13(z^2 + 3z - 2)\)</li>
</ul>
</li>
</ol>
<p><strong>Answer:</strong> \(13(z^2 + 3z - 2)\)</p>