- You will get a DNA strand sequence and you need to get the pair and return it as a 2D array of the base pairs. Keep in mind that the provided strand should be first always.
- There are two base case, A-T and C-G, these go both way. You can use regular expression, if statements of anything that you can think of.
- I would recommend using a switch, as it makes things a lot smoother.
- The result must be an array of arrays, so keep that in mind when pushing things.
Solution ahead!
function pair(str) {
// Return each strand as an array of two elements, the original and the pair.
var paired = [];
// Function to check with strand to pair.
var search = function(char) {
switch (char) {
case 'A':
paired.push(['A', 'T']);
break;
case 'T':
paired.push(['T', 'A']);
break;
case 'C':
paired.push(['C', 'G']);
break;
case 'G':
paired.push(['G', 'C']);
break;
}
};
// Loops through the input and pair.
console.log(char);
for (var i = 0; i < str.length; i++) {
search(str[i]);
}
return paired;
}
- The program is very simple, the best solution that I have come up with is to use a switch to catch all the possible four elements. Using if statements would take too much code. You could also use Regular Expressions.
- Since we have to the original and the pair, I decided to take all four cases instead of the base two.
- Create an empty array and use the
search
function to push the right values to the array and return them.
function pair(str) {
//define a map object with all pair possibilities
var map = {T:'A', A:'T', G:'C', C:'G'};
//split str into a a char Array
strArr = str.split('');
//replace each Array item with a 2d Array using map
for (var i=0;i<strArr.length;i++){
strArr[i]=[strArr[i], map[strArr[i]]];
}
return strArr;
}
- Read the comments
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