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To get a resource the filename must be a md5 of the filename. It would be helpful to get a resource and the decoded content by the filename itself.
Functions to implement : *GetResourceByFilename *GetContentByFilename
The text was updated successfully, but these errors were encountered:
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To get a resource the filename must be a md5 of the filename. It would be helpful to get a resource and the decoded content by the filename itself.
Functions to implement :
*GetResourceByFilename
*GetContentByFilename
The text was updated successfully, but these errors were encountered: