An elegant way to get file path from frontend to backend

[bengulliano]

Hi Please I would like to have a user select a file through a html input element -> send the file to the pywebio server -> and use rsync to copy the file to a remote destination (using subprocess.Popen).

Due to browser limitations the path to the file is not available, so the only option will be to save the file first in a temporary folder or create a symlink to the file and use the temporary file or symlink as a reference in the rsync operation.

I think this not a very elegant solution because of having to copy the file twice,

and another issue is that rsync will not accept a window.URL.createObjectURL(file) object as local file with error "The source and destination cannot both be remote", this is why I thought of copying the file to a temp location first

I wonder if you can recommend a more elegant solution.

[bengulliano]

For now I resolved to:
1: get the file-name from front-end/JS to pywebio back-end
2: use the filename to do a recursive search to find the local path.
3. use the path to file to execute rsync to copy the file to remote location

I must add that the application will always be installed and run locally on the user's PC.

[wang0618]

The first thing is to determine what file you want to be copied to the remote.

If you want to copy the file which is already on the pywebio server, then you don't need the file_upload() to get the file, just use input() to ask user input the file path.

If the file you want to be copied to the remote haven't existed on the pywebio server yet, then you must get the file by file_upload() and save its content to a tmp file to use rsync to copy to remote