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Copy path1302_Deepest_Leaves_Sum.cpp
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1302_Deepest_Leaves_Sum.cpp
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/*
Given a binary tree, return the sum of values of its deepest leaves.
Constraints:
The number of nodes in the tree is between 1 and 10^4.
The value of nodes is between 1 and 100.
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/deepest-leaves-sum
著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
*/
#include <stack>
using namespace std;
struct TreeNode {
int val;
TreeNode *left;
TreeNode *right;
TreeNode(int x) : val(x), left(NULL), right(NULL) {}
};
class Solution {
public:
int deepestLeavesSum(TreeNode* root) {
if(NULL==root) return 0;
stack<TreeNode*> s;
stack<int> d;
int max_depth = 0;
int res = 0;
s.push(root);
d.push(1);
while(!s.empty()){
TreeNode* tmp = s.top(); s.pop();
int depth = d.top(); d.pop();
if(tmp->left){
s.push(tmp->left);
d.push(depth+1);
}
if(tmp->right){
s.push(tmp->right);
d.push(depth+1);
}
if((NULL==tmp->left)&&(NULL==tmp->right)){
if(depth>max_depth){
max_depth = depth;
res = tmp->val;
}
else if(depth==max_depth){
res += tmp->val;
}
}
}
return res;
}
};