forked from shuboc/LeetCode-2
-
Notifications
You must be signed in to change notification settings - Fork 1
/
dungeon-game.py
108 lines (95 loc) · 3.72 KB
/
dungeon-game.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
from __future__ import print_function
# Time: O(m * n)
# Space: O(m + n)
#
# The demons had captured the princess (P) and imprisoned her
# in the bottom-right corner of a dungeon. T
# he dungeon consists of M x N rooms laid out in a 2D grid.
# Our valiant knight (K) was initially positioned in the top-left room
# and must fight his way through the dungeon to rescue the princess.
#
# The knight has an initial health point represented by a positive integer.
# If at any point his health point drops to 0 or below, he dies immediately.
#
# Some of the rooms are guarded by demons,
# so the knight loses health (negative integers) upon entering these rooms;
# other rooms are either empty (0's) or contain magic orbs that increase the knight's health (positive integers).
#
# In order to reach the princess as quickly as possible,
# the knight decides to move only rightward or downward in each step.
#
#
# Write a function to determine the knight's minimum initial health
# so that he is able to rescue the princess.
#
# For example, given the dungeon below, the initial health of
# the knight must be at least 7 if he follows the optimal path RIGHT-> RIGHT -> DOWN -> DOWN.
#
# Notes:
#
# The knight's health has no upper bound.
# Any room can contain threats or power-ups, even the first room the knight enters
# and the bottom-right room where the princess is imprisoned.
#
class Solution:
# @param dungeon, a list of lists of integers
# @return a integer
def calculateMinimumHP(self, dungeon):
DP = [float("inf") for _ in dungeon[0]]
DP[-1] = 1
for i in reversed(xrange(len(dungeon))):
DP[-1] = max(DP[-1] - dungeon[i][-1], 1)
for j in reversed(xrange(len(dungeon[i]) - 1)):
min_HP_on_exit = min(DP[j], DP[j + 1])
DP[j] = max(min_HP_on_exit - dungeon[i][j], 1)
return DP[0]
# Time: O(m * n logk), where k is the possible maximum sum of loses
# Space: O(m + n)
class Solution2:
# @param dungeon, a list of lists of integers
# @return a integer
def calculateMinimumHP(self, dungeon):
maximum_loses = 0
for rooms in dungeon:
for room in rooms:
if room < 0:
maximum_loses += abs(room)
return self.binarySearch(dungeon, maximum_loses)
def binarySearch(self, dungeon, maximum_loses):
start, end = 1, maximum_loses + 1
result = 0
while start < end:
mid = start + (end - start) / 2
if self.DP(dungeon, mid):
end = mid
else:
start = mid + 1
return start
def DP(self, dungeon, HP):
remain_HP = [0 for _ in dungeon[0]]
remain_HP[0] = HP + dungeon[0][0]
for j in xrange(1, len(remain_HP)):
if remain_HP[j - 1] > 0:
remain_HP[j] = max(remain_HP[j - 1] + dungeon[0][j], 0)
for i in xrange(1, len(dungeon)):
if remain_HP[0] > 0:
remain_HP[0] = max(remain_HP[0] + dungeon[i][0], 0)
else:
remain_HP[0] = 0
for j in xrange(1, len(remain_HP)):
remain = 0
if remain_HP[j - 1] > 0:
remain = max(remain_HP[j - 1] + dungeon[i][j], remain)
if remain_HP[j] > 0:
remain = max(remain_HP[j] + dungeon[i][j], remain)
remain_HP[j] = remain
return remain_HP[-1] > 0
if __name__ == "__main__":
dungeon = [[ -2, -3, 3], \
[ -5, -10, 1], \
[ 10, 30, -5]]
print(Solution().calculateMinimumHP(dungeon))
dungeon = [[ -200]]
print(Solution().calculateMinimumHP(dungeon))
dungeon = [[0, -3]]
print(Solution().calculateMinimumHP(dungeon))