forked from shuboc/LeetCode-2
-
Notifications
You must be signed in to change notification settings - Fork 1
/
trim-a-binary-search-tree.py
65 lines (61 loc) · 1.19 KB
/
trim-a-binary-search-tree.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
# Time: O(n)
# Space: O(h)
# Given a binary search tree and the lowest and highest boundaries as L and R,
# trim the tree so that all its elements lies in [L, R] (R >= L).
# You might need to change the root of the tree, so the result should
# return the new root of the trimmed binary search tree.
#
# Example 1:
# Input:
# 1
# / \
# 0 2
#
# L = 1
# R = 2
#
# Output:
# 1
# \
# 2
# Example 2:
# Input:
# 3
# / \
# 0 4
# \
# 2
# /
# 1
#
# L = 1
# R = 3
#
# Output:
# 3
# /
# 2
# /
# 1
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def trimBST(self, root, L, R):
"""
:type root: TreeNode
:type L: int
:type R: int
:rtype: TreeNode
"""
if not root:
return None
if root.val < L:
return self.trimBST(root.right, L, R)
if root.val > R:
return self.trimBST(root.left, L, R)
root.left, root.right = self.trimBST(root.left, L, R), self.trimBST(root.right, L, R)
return root