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10171.cpp
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10171.cpp
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//BISMILLAHIRRAHMANIRRAHIM
/*
manus tar shopner soman boro
Author :: Shakil Ahmed
.............AUST_CSE27.........
prob ::
Type ::
verdict::
*/
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>
#include <math.h>
#include <limits.h>
#include <set>
#include <algorithm>
#include <iostream>
#include <vector>
#include <stack>
#include <string>
#include <list>
#include <map>
#include <queue>
#include <sstream>
#include <utility>
#define pb push_back
#define mp make_pair
#define pi acos(-1.0)
#define ff first
#define LL long long
#define ss second
#define rep(i,n) for(i = 0; i < n; i++)
#define REP(i,n) for(i=n;i>=0;i--)
#define FOR(i,a,b) for(int i = a; i <= b; i++)
#define ROF(i,a,b) for(int i = a; i >= b; i--)
#define re return
#define QI queue<int>
#define SI stack<int>
#define pii pair <int,int>
#define MAX
#define MOD
#define INF 1<<30
#define SZ(x) ((int) (x).size())
#define ALL(x) (x).begin(), (x).end()
#define sqr(x) ((x) * (x))
#define memo(a,b) memset((a),(b),sizeof(a))
#define G() getchar()
#define MAX3(a,b,c) max(a,max(b,c))
double const EPS=3e-8;
using namespace std;
template< class T > T gcd(T a, T b) { return (b != 0 ? gcd<T>(b, a%b) : a); }
template< class T > T lcm(T a, T b) { return (a / gcd<T>(a, b) * b); }
template <class T> inline T bigmod(T p,T e,T M)
{
if(e==0)return 1;
if(e%2==0){LL t=bigmod(p,e/2,M);return (T)((t*t)%M);}
return (T)((LL)bigmod(p,e-1,M)*(LL)p)%M;
}
template <class T> inline T modinverse(T a,T M){return bigmod(a,M-2,M);}
//Fast Reader
template<class T>inline bool read(T &x){int c=getchar();int sgn=1;while(~c&&c<'0'||c>'9'){if(c=='-')sgn=-1;c=getchar();}for(x=0;~c&&'0'<=c&&c<='9';c=getchar())x=x*10+c-'0'; x*=sgn; return ~c;}
/* ************************************** My code start here ****************************************** */
const int maxn = 30 ;
typedef long long ll ;
ll dp1[maxn][maxn] , dp2[maxn][maxn] ;
int Y , M , n = 26;
void CLEAN()
{
int i , j ;
rep(i,n)
{
rep(j,n) dp1[i][j] = dp2[i][j] = (1<<29);
}
}
bool input()
{
char A , B , C , D ;
ll cst ;
int x , y , i , m;
cin >> m ;
// cout<<" n " << n << endl;
if(!m ) return 0;
while(m--)
{
// printf("here\n");
// getchar();
cin >> A >> B >> C >> D;
read(cst);
// read(A) , read(B) , read(C) , read(D) , read(cst);
// cout<<" A " << A << B << C << D << cst << endl;
x = C - 'A';
y = D - 'A';
if(A=='Y')
{
if( B == 'B' )
{
dp1[x][y] = min(dp1[x][y],cst);
dp1[y][x] = min(dp1[y][x],cst);
}
else dp1[x][y] = min(dp1[x][y],cst);
}
else
{
if( B == 'B' )
{
dp2[x][y] = min(dp2[x][y],cst);
dp2[y][x] = min(dp2[y][x],cst);
}
else dp2[x][y] = min(dp2[x][y],cst);
}
}
cin >> A >> B ;
Y = A - 'A';
M = B - 'A';
rep(i,n) dp1[i][i] = dp2[i][i] = 0 ;
return 1;
}
void solve()
{
int i , j , k ;
rep(k,n) rep(i,n) rep(j,n)
{
if(dp1[i][j] > dp1[i][k] + dp1[k][j] ) dp1[i][j] = dp1[i][k] + dp1[k][j];
if(dp2[i][j] > dp2[i][k] + dp2[k][j] ) dp2[i][j] = dp2[i][k] + dp2[k][j];
}
ll ans = ( 1 << 29 ) ;
for ( i = 0 ; i < n ; i++ )
{
if(dp1[Y][i] == (1<<29) || dp2[M][i] == (1<<29) ) continue;
if(ans > dp1[Y][i] + dp2[M][i])
{
ans = dp1[Y][i] + dp2[M][i] ;
}
}
if(ans == (1<<29))
{
printf("You will never meet.\n");
}
else
{
cout<<ans;
for ( i = 0 ; i < n ; i++ )
{
if( ans == dp1[Y][i] + dp2[M][i])
{
cout<<" "<< char('A'+i);
}
}
cout<<endl;
}
}
int main()
{
// ios :: sync_with_stdio(false);
// freopen("input.txt","r",stdin);
//freopen("output.txt","w",stdout);
CLEAN();
while(input())
{
solve();
CLEAN();
}
return 0;
}