Given a non-empty array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
Example 1:
Input: [2,2,1] Output: 1
Example 2:
Input: [4,1,2,1,2] Output: 4
class Solution:
def singleNumber(self, nums: List[int]) -> int:
res = 0
for num in nums:
res ^= num
return res
class Solution {
public int singleNumber(int[] nums) {
int res = 0;
for (int num : nums) {
res ^= num;
}
return res;
}
}