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Description

Let's call any (contiguous) subarray B (of A) a mountain if the following properties hold:

    <li><code>B.length &gt;= 3</code></li>
    
    <li>There exists some <code>0 &lt; i&nbsp;&lt; B.length - 1</code> such that <code>B[0] &lt; B[1] &lt; ... B[i-1] &lt; B[i] &gt; B[i+1] &gt; ... &gt; B[B.length - 1]</code></li>
    

(Note that B could be any subarray of A, including the entire array A.)

Given an array A of integers, return the length of the longest mountain

Return 0 if there is no mountain.

Example 1:

Input: [2,1,4,7,3,2,5]

Output: 5

Explanation: The largest mountain is [1,4,7,3,2] which has length 5.

Example 2:

Input: [2,2,2]

Output: 0

Explanation: There is no mountain.

Note:

    <li><code>0 &lt;= A.length &lt;= 10000</code></li>
    
    <li><code>0 &lt;= A[i] &lt;= 10000</code></li>
    

Follow up:

    <li>Can you solve it using only one pass?</li>
    
    <li>Can you solve it in <code>O(1)</code> space?</li>
    

Solutions

Python3

Java

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