难度:非常简单
编写一种算法,若M × N矩阵中某个元素为0,则将其所在的行与列清零。
输入:
[
[1,1,1],
[1,0,1],
[1,1,1]
]
输出:
[
[1,0,1],
[0,0,0],
[1,0,1]
]
输入:
[
[0,1,2,0],
[3,4,5,2],
[1,3,1,5]
]
输出:
[
[0,0,0,0],
[0,4,5,0],
[0,3,1,0]
]
/**
* @description: 时间复杂度 O(N^2) 空间复杂度 O(N)
* @return {*}
* @param {number} matrix
*/
export function setZeroes(matrix: number[][]): void {
const m = matrix.length
const n = matrix[0].length
const row: Set<number> = new Set()
const col: Set<number> = new Set()
for (let i = 0; i < m; i++) {
for (let j = 0; j < n; j++) {
if (!matrix[i][j]) {
row.add(i)
col.add(j)
}
}
}
row.forEach(item => {
for (let i = 0; i < n; i++)
matrix[item][i] = 0
})
col.forEach(item => {
for (let i = 0; i < m; i++)
matrix[i][item] = 0
})
}