The Employee table holds all employees. Every employee has an Id, and there is also a column for the department Id.
Id | Name | Salary | DepartmentId |
---|---|---|---|
1 | Joe | 70000 | 1 |
2 | Henry | 80000 | 2 |
3 | Sam | 60000 | 2 |
4 | Max | 90000 | 1 |
5 | Janet | 69000 | 1 |
6 | Randy | 85000 | 1 |
The Department table holds all departments of the company.
Id | Name |
---|---|
1 | IT |
2 | Sales |
Write a SQL query to find employees who earn the top three salaries in each of the department. For the above tables, your SQL query should return the following rows.
Department | Employee | Salary |
---|---|---|
IT | Max | 90000 |
IT | Randy | 85000 |
IT | Joe | 70000 |
Sales | Henry | 80000 |
Sales | Sam | 60000 |
select `d`.`Name` as `Department`, `e1`.`Name` as `Employee`, `e1`.`Salary` from `Employee` `e1`,
`Employee` `e2`, `Department` `d`
where `e1`.`DepartmentId` = `e2`.`DepartmentId`
and `e1`.`Salary` <= `e2`.`Salary`
and `d`.`Id` = `e1`.`DepartmentId`
group by `e1`.`Id`
having count(distinct `e2`.`Salary`) <= 3
order by `Department`, `Salary` desc;;
If you have a better solution, you can star and fork Leetcode-database-problem then create a pull request.