The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.
Id | Name | Salary | ManagerId |
---|---|---|---|
1 | Joe | 70000 | 3 |
2 | Henry | 80000 | 4 |
3 | Sam | 60000 | NULL |
4 | Max | 90000 | NULL |
Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.
Employee |
---|
Joe |
select `e1`.`Name` as `Employee` from `Employee` `e1`, `Employee` `e2`
where `e1`.`ManagerId` = `e2`.`Id`
and `e1`.`Salary` > `e2`.`Salary`;
If you have a better solution, you can star and fork Leetcode-database-problem then create a pull request.