The Trips table holds all taxi trips. Each trip has a unique Id, while Client_Id and Driver_Id are both foreign keys to the Users_Id at the Users table. Status is an ENUM type of (‘completed’, ‘cancelled_by_driver’, ‘cancelled_by_client’).
Id | Client_Id | Driver_Id | City_Id | Status | Request_at |
---|---|---|---|---|---|
1 | 1 | 10 | 1 | completed | 2013-10-01 |
2 | 2 | 11 | 1 | cancelled_by_driver | 2013-10-01 |
3 | 3 | 12 | 6 | completed | 2013-10-01 |
4 | 4 | 13 | 6 | cancelled_by_client | 2013-10-01 |
5 | 1 | 10 | 1 | completed | 2013-10-02 |
6 | 2 | 11 | 6 | completed | 2013-10-02 |
7 | 3 | 12 | 6 | completed | 2013-10-02 |
8 | 2 | 12 | 12 | completed | 2013-10-03 |
9 | 3 | 10 | 12 | completed | 2013-10-03 |
10 | 4 | 13 | 12 | cancelled_by_driver | 2013-10-03 |
The Users table holds all users. Each user has an unique Users_Id, and Role is an ENUM type of (‘client’, ‘driver’, ‘partner’).
Users_Id | Banned | Role |
---|---|---|
1 | No | client |
2 | Yes | client |
3 | No | client |
4 | No | client |
10 | No | driver |
11 | No | driver |
12 | No | driver |
13 | No | driver |
Write a SQL query to find the cancellation rate of requests made by unbanned users between Oct 1, 2013 and Oct 3, 2013. For the above tables, your SQL query should return the following rows with the cancellation rate being rounded to two decimal places.
Day | Cancellation Rate |
---|---|
2013-10-01 | 0.33 |
2013-10-02 | 0.00 |
2013-10-03 | 0.50 |
select `t1`.`Day` as `Day`, round(ifnull(`t2`.`num`/`t1`.`num`, 0), 2) as `Cancellation Rate` from
(select `Trips`.`Request_at` as `Day`, count(*) as `num` from `Trips` join `Users`
on `Users`.`Users_Id` = `Trips`.`Client_Id`
and `Users`.`Banned` = 'No'
and `Trips`.`Request_at` in ('2013-10-01', '2013-10-02', '2013-10-03')
group by `Trips`.`Request_at`
) as `t1`
left join
(select `Trips`.`Request_at` as `Day`, count(*) as `num` from `Trips` join `Users`
on `Users`.`Users_Id` = `Trips`.`Client_Id`
and `Users`.`Banned` = 'No'
and `Trips`.`Status` != 'completed'
and `Trips`.`Request_at` in ('2013-10-01', '2013-10-02', '2013-10-03')
group by `Trips`.`Request_at`
) as `t2`
on `t1`.`Day` = `t2`.`Day`
order by `Day` asc;;
If you have a better solution, you can star and fork Leetcode-database-problem then create a pull request.