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CS50P - Problem Set 2

camelCase

Implement a program that prompts the user for the name of a variable in camel case and outputs the corresponding name in snake case. Assume that the user's input will indeed be in camel case.

for c in list[1:] # Starting at second character
list.append(word)
.lower()
"_".join(list) # Joins list elements into a string with specified separator

Coke Machine

Coke machine sells a bottle for 50 cents and only accepts 25, 10 and 5 cents.

Implement a program that prompts the user to insert a coin, one at a time, each time informing the user of the amount due.

  • Once the user has inputted at least 50 cents, output how many cents in change the user is owed.
  • Assume that the user will only input integers, and ignore any integer that isn't accepted
while count < 50:
    …
if coin == 25 or coin == 10 …
# Ensure the change is not negative
print(f"Change Owed: {count -  50}")

Just setting up my twttr

Implement a program that prompts the user for a str of text and then outputs that same text but with all vowels A, E, I, O, and U omitted, whether imputed in uppercase or lowercase.

.append()
"".join(list)

Vanity Plates

Implement a program that prompts the user for a vanity plate and then output Valid if it meets all of the requirements or Invalid if it does not.

  • Assume that any letters in the user’s input will be uppercase
  • Is_valid() returns True if s meets all the requirements and False if it does not.
  • Assume that s will be a str

Requirements:

  • Start with at least 2 letters s[0].isalpha() == False or s[1].isalpha() == False
  • Maximum 6 characters (letters or numbers) len(6)
  • Minimum 2 characters len(2)
  • Numbers must come at the end after the letters if c.isalpha() and i != 0 (range) and s[i - 1].isdigit()
  • First number can't be 0 (if c == "0") and no digit was found before
  • No periods, spaces, or punctuation marks if c.isalnum() == False:

zero_digit_found = False
# If current char is a digit equal to zero
# and there was no digit before it (first char is 0) return False
if c.isdigit():
    if c == "0" and zero_digit_found == False:
        return False
    elif c != "0":
        zero_digit_found = True
for i, c in enumerate(s)

Nutrition Facts

Implement a program that prompts users to input a fruit (case-insensitive) and outputs the number of calories in one portion of that fruit, per the FDA’s poster for fruits.

  • Assume that users will input fruits exactly as written in the poster.
  • Ignore any input that isn't a fruit
dictionary = {"key1": "value1", "key2": "value2"}

if fruit in fruit_dict:
	return fruit_dict[fruit]

For the function not to return dictionary value: In main(), only print if result != None