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Copy path297. Serialize and Deserialize Binary Tree.py
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297. Serialize and Deserialize Binary Tree.py
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# Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another computer environment.
# Design an algorithm to serialize and deserialize a binary tree. There is no restriction on how your serialization/deserialization algorithm should work. You just need to ensure that a binary tree can be serialized to a string and this string can be deserialized to the original tree structure.
# For example, you may serialize the following tree
# 1
# / \
# 2 3
# / \
# 4 5
# as "[1,2,3,null,null,4,5]", just the same as how LeetCode OJ serializes a binary tree. You do not necessarily need to follow this format, so please be creative and come up with different approaches yourself.
# Note: Do not use class member/global/static variables to store states. Your serialize and deserialize algorithms should be stateless.
# Credits:
# Special thanks to @Louis1992 for adding this problem and creating all test cases.
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Codec:
# Level order Traverse empty is equals to '#'
def serialize(self, root):
"""Encodes a tree to a single string.
:type root: TreeNode
:rtype: str
"""
if not root:
return ""
queue = [root]
res = []
while queue:
node = queue.pop(0)
if node:
queue.append(node.left)
queue.append(node.right)
res.append(str(node.val) if node else "#")
# -3 -> str -3#
# 3,1,2,'#','#','#','#'
return ",".join(res).strip(',')
def deserialize(self, data):
"""Decodes your encoded data to tree.
:type data: str
:rtype: TreeNode
"""
if not data:
return None
nodes = []
for i in data.split(','):
if i != '#':
nodes.append(TreeNode(int(i)))
else:
nodes.append(None)
queue = [nodes[0]]
index = 1
while queue:
node = queue.pop(0)
if index < len(nodes) and nodes[index]:
node.left = nodes[index]
queue.append(nodes[index])
if index+1 < len(nodes) and nodes[index+1]:
node.right = nodes[index+1]
queue.append(nodes[index+1])
index += 2
return nodes[0]
# Your Codec object will be instantiated and called as such:
# codec = Codec()
# codec.deserialize(codec.serialize(root))