Skip to content

Add solution and test-cases for problem 1865 #1253

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Open
wants to merge 1 commit into
base: main
Choose a base branch
from
Open
Show file tree
Hide file tree
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
40 changes: 24 additions & 16 deletions leetcode/1801-1900/1865.Finding-Pairs-With-a-Certain-Sum/README.md
Original file line number Diff line number Diff line change
@@ -1,28 +1,36 @@
# [1865.Finding Pairs With a Certain Sum][title]

> [!WARNING|style:flat]
> This question is temporarily unanswered if you have good ideas. Welcome to [Create Pull Request PR](https://github.com/kylesliu/awesome-golang-algorithm)

## Description
You are given two integer arrays `nums1` and `nums2`. You are tasked to implement a data structure that supports queries of two types:

**Example 1:**
1. **Add** a positive integer to an element of a given index in the array `nums2`.
2. **Count** the number of pairs `(i, j)` such that `nums1[i] + nums2[j]` equals a given value (`0 <= i < nums1.length` and `0 <= j < nums2.length`).

```
Input: a = "11", b = "1"
Output: "100"
```
Implement the `FindSumPairs` class:

## 题意
> ...
- `FindSumPairs(int[] nums1, int[] nums2)` Initializes the `FindSumPairs` object with two integer arrays `nums1` and `nums2`.
- `void add(int index, int val)` Adds `val` to `nums2[index]`, i.e., apply `nums2[index] += val`.
- `int count(int tot)` Returns the number of pairs `(i, j)` such that `nums1[i] + nums2[j] == tot`.

## 题解
**Example 1:**

### 思路1
> ...
Finding Pairs With a Certain Sum
```go
```

Input
["FindSumPairs", "count", "add", "count", "count", "add", "add", "count"]
[[[1, 1, 2, 2, 2, 3], [1, 4, 5, 2, 5, 4]], [7], [3, 2], [8], [4], [0, 1], [1, 1], [7]]
Output
[null, 8, null, 2, 1, null, null, 11]

Explanation
FindSumPairs findSumPairs = new FindSumPairs([1, 1, 2, 2, 2, 3], [1, 4, 5, 2, 5, 4]);
findSumPairs.count(7); // return 8; pairs (2,2), (3,2), (4,2), (2,4), (3,4), (4,4) make 2 + 5 and pairs (5,1), (5,5) make 3 + 4
findSumPairs.add(3, 2); // now nums2 = [1,4,5,4,5,4]
findSumPairs.count(8); // return 2; pairs (5,2), (5,4) make 3 + 5
findSumPairs.count(4); // return 1; pair (5,0) makes 3 + 1
findSumPairs.add(0, 1); // now nums2 = [2,4,5,4,5,4]
findSumPairs.add(1, 1); // now nums2 = [2,5,5,4,5,4]
findSumPairs.count(7); // return 11; pairs (2,1), (2,2), (2,4), (3,1), (3,2), (3,4), (4,1), (4,2), (4,4) make 2 + 5 and pairs (5,3), (5,5) make 3 + 4
```

## 结语

Expand Down
Original file line number Diff line number Diff line change
@@ -1,5 +1,58 @@
package Solution

func Solution(x bool) bool {
return x
type FindSumPairs struct {
c1, c2 map[int]int
n2 []int
}

func Constructor(nums1 []int, nums2 []int) FindSumPairs {
f := FindSumPairs{
c1: map[int]int{}, c2: map[int]int{}, n2: nums2,
}
for _, n := range nums1 {
f.c1[n]++
}
for _, n := range nums2 {
f.c2[n]++
}
return f
}

func (this *FindSumPairs) Add(index int, val int) {
source := this.n2[index]
this.n2[index] += val
this.c2[source]--
if this.c2[source] == 0 {
delete(this.c2, source)
}
this.c2[this.n2[index]]++
}

func (this *FindSumPairs) Count(tot int) int {
ans := 0
for k, c := range this.c1 {
if c1, ok := this.c2[tot-k]; ok {
ans += c * c1
}
}
return ans
}

type op struct {
name byte
a, b int
}

func Solution(nums1, nums2 []int, ops []op) []int {
var ans []int
c := Constructor(nums1, nums2)
for _, o := range ops {
if o.name == 'a' {
c.Add(o.a, o.b)
continue
}
ans = append(ans, c.Count(o.a))
}
return ans

}
Original file line number Diff line number Diff line change
Expand Up @@ -9,31 +9,52 @@ import (
func TestSolution(t *testing.T) {
// 测试用例
cases := []struct {
name string
inputs bool
expect bool
name string
nums1, nums2 []int
ops []op
expect []int
}{
{"TestCase", true, true},
{"TestCase", true, true},
{"TestCase", false, false},
{"TestCase1", []int{1, 1, 2, 2, 2, 3}, []int{1, 4, 5, 2, 5, 4}, []op{
{
name: 'c', a: 7,
},
{
name: 'a', a: 3, b: 2,
},
{
name: 'c', a: 8,
},
{
name: 'c', a: 4,
},
{
name: 'a', a: 0, b: 1,
},
{
name: 'a', a: 1, b: 1,
},
{
name: 'c', a: 7,
},
}, []int{8, 2, 1, 11}},
}

// 开始测试
for i, c := range cases {
t.Run(c.name+" "+strconv.Itoa(i), func(t *testing.T) {
got := Solution(c.inputs)
got := Solution(c.nums1, c.nums2, c.ops)
if !reflect.DeepEqual(got, c.expect) {
t.Fatalf("expected: %v, but got: %v, with inputs: %v",
c.expect, got, c.inputs)
t.Fatalf("expected: %v, but got: %v, with inputs: %v %v %v",
c.expect, got, c.nums1, c.nums2, c.ops)
}
})
}
}

// 压力测试
// 压力测试
func BenchmarkSolution(b *testing.B) {
}

// 使用案列
// 使用案列
func ExampleSolution() {
}
Loading