linked list exercise(Sumitra) #44
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CheezItMan
reviewed
Oct 20, 2021
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| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
| def get_first(self): |
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| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
| def add_first(self, value): |
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👍 However this is O(1) for both time/space complexity.
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| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def search(self, value): |
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| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def length(self): |
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| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def get_at_index(self, index): |
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| # Time Complexity: O(1) | ||
| # Space Complexity: O(n) | ||
| def add_last(self, value): |
| current_node = self.head | ||
| while current_node.next != None: | ||
| current_node = current_node.next | ||
| current_node.next = new_node | ||
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| # method to return the max value in the linked list | ||
| # returns the data value and not the node | ||
| def find_max(self): |
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| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def delete(self, value): |
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| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
| def visit(self): |
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| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
| def reverse(self): |
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👍 However the space complexity is O(1) because you're not creating new nodes.
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