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Abigail C - Rock #55

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Abigail C - Rock #55

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ChaAbby
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@ChaAbby ChaAbby commented Jan 13, 2022

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@CheezItMan CheezItMan left a comment

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Nice work Abigail, you hit the learning goals here. I left some minor feedback for you, but this was well done.

Comment on lines +22 to 24
# Time Complexity: O(1)
# Space Complexity: O(1)
def get_first(self):

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👍

Comment on lines +32 to 34
# Time Complexity: O(1)
# Space Complexity: O(1)
def add_first(self, value):

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👍

Comment on lines +35 to +36
new_node = Node(value, next_node=self.head)
self.head = new_node

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Can be rewritten

Suggested change
new_node = Node(value, next_node=self.head)
self.head = new_node
self.head = Node(value, next_node=self.head)

Comment on lines +40 to 43
# Time Complexity: O(n)
# Space Complexity: O(1)

def search(self, value):

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👍

Comment on lines +53 to 56
# Time Complexity: O(n)
# Space Complexity: O(1)

def length(self):

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👍

Comment on lines +124 to +126
# Time Complexity: O(n)
# Space Complexity: O(1)
def delete(self, val):

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👍

Comment on lines +144 to 146
# Time Complexity: O(n)
# Space Complexity: O(n)
def visit(self):

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👍

Comment on lines +158 to 160
# Time Complexity: O(n)
# Space Complexity: O(1)
def reverse(self):

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👍

Comment on lines +174 to 176
# Time Complexity: O(n)
# Space Complexity: O(1)
def find_middle_value(self):

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👍 This works, but you could either:

  • use the length method
  • or have a fast and slow node reference where the fast move 2 nodes with each iteration and the slow moves one. Then when the fast reaches the end, the slow is referring to the middle node.

# # find the nth node from the end and return its value
# # assume indexing starts at 0 while counting to n
# # Time Complexity: O(n)
# # Space Complexity: O(1)
def find_nth_from_end(self, n):

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👍 this works with similar feedback to find middle.

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2 participants