Pine C16 Eunice & Lilly #30
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CheezItMan
reviewed
Sep 28, 2021
| @@ -1,11 +1,93 @@ | |||
| import random | |||
| def draw_letters(): | |||
| tile_bag.remove(letter) | ||
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| return tile_list | ||
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| def uses_available_letters(word, letter_bank): |
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👍 Nice work, this is a clever way to solve this.
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| value1=["A","E","I","O","U","L","N", "R", "S", "T"] | ||
| value_2=["D", "G"] | ||
| value_3=["B", "C", "M", "P"] | ||
| value_4=["F", "H", "V", "W", "Y"] | ||
| value_5=["K"] | ||
| value_8=["J", "X"] | ||
| value_10=["Q", "Z"] |
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This works, but It involves a lot of hardcoded if statements. This could also be solved with a dictionary, using either a set of letters as values and scores as values, or individual letters as keys and points as values.
For example
letter_scores = {
{"A","E","I","O","U","L","N", "R", "S", "T"}: 1,
{"D", "G"}: 2,
...Or:
letter_scores = {
'A': 1,
'B': 3,
'C': 3,
...Then you can solve the problem with a more compact loop.
| total+=10 | ||
| if len(modified_word)>=7: | ||
| total+=8 | ||
| return(total) | ||
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| def get_highest_word_score(word_list): |
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Clever use of max and min to determine the winner.
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