Maple - Tiana Wofford and Rachael McBride #47
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tgoslee
reviewed
Oct 5, 2021
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| letter_pool = [] | ||
| for letter, frequency in LETTER_KEY.items(): | ||
| for number in range(frequency): | ||
| letter_pool.append(letter) |
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I would suggest looking into copy() and deepcopy() to create a copy of your letter pool https://docs.python.org/3/library/copy.html
tgoslee
reviewed
Oct 5, 2021
| if user_hand.count(letter_to_add) < LETTER_KEY[letter_to_add]: | ||
| user_hand.append(letter_to_add) | ||
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| return user_hand | ||
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| def uses_available_letters(word, letter_bank): |
tgoslee
reviewed
Oct 5, 2021
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| for letter in word: | ||
| if letter in ['A', 'E', 'I', 'O', 'U', 'L', 'N', 'R', 'S', 'T']: | ||
| score += 1 | ||
| elif letter in ['D', 'G']: | ||
| score += 2 | ||
| elif letter in ['B', 'C', 'M', 'P']: | ||
| score += 3 | ||
| elif letter in ['F', 'H', 'V', 'W', 'Y']: | ||
| score += 4 | ||
| elif letter in ['K']: | ||
| score += 5 | ||
| elif letter in ['J', 'X']: | ||
| score += 8 | ||
| elif letter in ['Q', 'Z']: | ||
| score += 10 |
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You could create a dictionary with these as key-value pairs. Or you could create a constant global value that holds this data and then do something like:
Suggested change
| for letter in word: | |
| if letter in ['A', 'E', 'I', 'O', 'U', 'L', 'N', 'R', 'S', 'T']: | |
| score += 1 | |
| elif letter in ['D', 'G']: | |
| score += 2 | |
| elif letter in ['B', 'C', 'M', 'P']: | |
| score += 3 | |
| elif letter in ['F', 'H', 'V', 'W', 'Y']: | |
| score += 4 | |
| elif letter in ['K']: | |
| score += 5 | |
| elif letter in ['J', 'X']: | |
| score += 8 | |
| elif letter in ['Q', 'Z']: | |
| score += 10 | |
| for letter in word: | |
| score += LETTER_VALUES[letter.upper()] |
tgoslee
reviewed
Oct 5, 2021
| if len(word) >= 7 and len(word) <= 10: | ||
| score += 8 | ||
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| return score | ||
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| def get_highest_word_score(word_list): |
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Great work! I added some comments on refactoring and using constant global variables! |
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