Queues - Erica Case - Recursion tracing #16
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sudocrystal
reviewed
Apr 18, 2017
| else | ||
| return s[0] + mystery5(s[1..-1]) | ||
| end | ||
| end |
| return "" | ||
| end | ||
| return s[(s.length - 1)] + mystery6(s[0...(s.length-1)]) | ||
| end |
| else | ||
| return (n%10) * n / n.abs + mystery2(n/10) | ||
| end | ||
| end |
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This looks like it may work - but is a little hard to follow. Here's another solution that's perhaps more readable.
def mystery2(n)
if n < 0
return -1 * mystery2(-n)
elsif n < 10
return n
else
return (n%10) + mystery2(n/10)
end
end
|
Nice work! |
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Recursion Tracing
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Comprehension Questions