2 0f 3 exercises exercised #3
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The ordering I assumed only checked numbers on the diagonal and superdiagonal matrix elements. I need to check all the matrix elements: (n - i)*(n - j) = n**2 - (i + j)*n + i*j. However, my new, far simpler idea is to assume that the largest palindrome in the set (or square matrix with elements (n - i)*(n - j) for integers 0 <= i,j <= n) is much closer to n**2 than to 0: n**2 > largest_base_ten_palindrome >> 0.
The assumption used is helpful to find the larges palindrome without permuting the whole parameter space, however the palindrome itself can be found in multiple binary combinations of the prime factors of the palindrome.
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