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ZA-ITP-May-2025 | Christian Mayamba | Module-Data-Groups | Week 2 #699
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for (const item of array) { | ||
if (result[item]) { | ||
result[item] = result[item] + 1; | ||
} else { | ||
result[item] = 1; | ||
} | ||
} | ||
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Well done! As a challenge, can you refactor the code with an array method and ternary operator so the code can be more simple and concise?
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Good job!
In the real world, URLs are usually encoded with percent encoding to represent special characters. In URL, & can be used as a separator (key=value&key=value...) or special character within a key or value. if we were to use & as a special character, we need to encode it.
Can you refactor the code so that parseQueryString("a%25b=c%26d") results in { "a%b": "c&d" }?
FYI, %25 is same as %, %26 is same as &
Hi @c-mayamba. Thank you for refactoring the code accordingly. I left two more reviews. |
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