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Include BomRef within Component hash calculation #678
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I see why you go with
self.bom_ref.value
instead ofself.bom_ref
.BomRef.__hash__
exists and is implemented to account for the__id__
of the "empty" object entity, so thatNone
values are unequal.Your implementation does not do so, and may cause unexpected behaviour here.
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Indeed I had originally only added
self.bom_ref
, but that would then not deduplicate theNone
s. Is there a reason for theBomRef
hash to include the id? It seems superfluous when there is a unique identifier. Note also that the code claims a random UUIDv4 should have been assigned when there is no ref, but this is not actually the case