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- 문제 | ||
- 유료 : https://leetcode.com/problems/encode-and-decode-strings/ | ||
- 무료 : https://www.lintcode.com/problem/659/ | ||
- time complexity : O(n) | ||
- space complexity : O(n \* m), m은 각 문자열 길이의 평균 | ||
- 블로그 링크 : https://algorithm.jonghoonpark.com/2024/05/29/leetcode-271 | ||
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```java | ||
public String encode(List<String> strs) { | ||
StringBuilder sb = new StringBuilder(); | ||
for (String str : strs) { | ||
sb.append(str.replace("%", "%25").replace(",", "%2C")).append(","); | ||
} | ||
return sb.length() > 0 ? sb.toString() : ""; | ||
} | ||
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public List<String> decode(String str) { | ||
List<String> decodedList = new ArrayList<>(); | ||
if (str.length() > 0) { | ||
int commaIndex = str.indexOf(","); | ||
while (commaIndex > -1) { | ||
decodedList.add(str.substring(0, commaIndex).replace("%2C", ",").replace("%25", "%")); | ||
str = str.substring(commaIndex + 1); | ||
commaIndex = str.indexOf(","); | ||
} | ||
} | ||
return decodedList; | ||
} | ||
``` |
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- 문제 : https://leetcode.com/problems/longest-consecutive-sequence/ | ||
- time complexity : O(n) | ||
- space complexity : O(n) | ||
- 블로그 링크 : https://algorithm.jonghoonpark.com/2024/05/28/leetcode-128 | ||
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```java | ||
public int longestConsecutive(int[] nums) { | ||
Set<Integer> set = new HashSet<>(); | ||
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for(int num : nums) { | ||
set.add(num); | ||
} | ||
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int max = 0; | ||
for(int num : set) { | ||
if (!set.contains(num - 1)) { | ||
int current = 1; | ||
while (set.contains(num + 1)) { | ||
current++; | ||
num++; | ||
} | ||
max = Math.max(current, max); | ||
} | ||
} | ||
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return max; | ||
} | ||
``` |
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- 문제 : https://leetcode.com/problems/product-of-array-except-self/ | ||
- time complexity : O(n) | ||
- space complexity : O(n) | ||
- 블로그 링크 : https://algorithm.jonghoonpark.com/2024/05/08/leetcode-238 | ||
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## case 나눠서 풀기 | ||
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```java | ||
public int[] productExceptSelf(int[] nums) { | ||
int[] products = new int[nums.length]; | ||
int result = 1; | ||
int zeroCount = 0; | ||
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int p = 0; | ||
while (p < nums.length) { | ||
if (nums[p] != 0) { | ||
result *= nums[p]; | ||
} else { | ||
zeroCount++; | ||
if (zeroCount >= 2) { | ||
Arrays.fill(products, 0); | ||
return products; | ||
} | ||
} | ||
p++; | ||
} | ||
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if (zeroCount == 1) { | ||
p = 0; | ||
while (p < nums.length) { | ||
if (nums[p] == 0) { | ||
products[p] = result; | ||
} | ||
p++; | ||
} | ||
} else { | ||
p = 0; | ||
while (p < nums.length) { | ||
products[p] = result / nums[p]; | ||
p++; | ||
} | ||
} | ||
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return products; | ||
} | ||
``` | ||
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## 재밋는 방법으로 풀기 (prefixProd) | ||
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```java | ||
public int[] productExceptSelf(int[] nums) { | ||
int[] result = new int[nums.length]; | ||
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int[] prefixProd = new int[nums.length]; | ||
int[] suffixProd = new int[nums.length]; | ||
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prefixProd[0] = nums[0]; | ||
for (int i = 1; i < nums.length; i++) { | ||
prefixProd[i] = prefixProd[i-1] * nums[i]; | ||
} | ||
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suffixProd[nums.length - 1] = nums[nums.length - 1]; | ||
for (int i = nums.length - 2; i > -1; i--) { | ||
suffixProd[i] = suffixProd[i + 1] * nums[i]; | ||
} | ||
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result[0] = suffixProd[1]; | ||
result[nums.length - 1] = prefixProd[nums.length - 2]; | ||
for (int i = 1; i < nums.length - 1; i++) { | ||
result[i] = prefixProd[i - 1] * suffixProd[i + 1]; | ||
} | ||
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return result; | ||
} | ||
``` |