[KwonNayeon] Week 13 solutions #1621
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hi-rachel
approved these changes
Jun 29, 2025
| 3. 리스트의 요소 갯수가 홀수/짝수일 때의 경우를 나눠서 median 값을 구함 | ||
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| 메모: | ||
| - heap이 익숙하지 않아서 일단 리스트로 문제를 풀었습니다. |
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저도 heap 문법이 익숙하지 않아서 찾아보며 했는데 막상 써보면 쉽더라구여.
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저도 heap으로 도전해봐야겠어요! 감사합니당 👍
| else: | ||
| mid1 = self.nums[n // 2 - 1] | ||
| mid2 = self.nums[n // 2] | ||
| return (mid1 + mid2) / 2.0 |
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소수임을 명시하기 위해 2.0을 쓰신 점 배워갑니다.
| @@ -13,12 +13,19 @@ | |||
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| 풀이방법: | |||
| 1. Base case: 빈 배열/none일 때 True 반환 | |||
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풀이 방법, 메모 등 정리를 정말 잘하시는거 같아요. 한 문제를 풀어도 기억에 오래 남을거 같은 좋은 방법이네요 잘 보고 갑니다 👍🏻😃
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@hi-rachel 님 꼼꼼한 리뷰 감사합니다! |
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