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[chrisjune] WEEK 02 Solutions #1769
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from typing import List | ||
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class Solution: | ||
def threeSum(self, nums: List[int]) -> List[List[int]]: | ||
if len(nums) >= 3 and set(nums) == set([0]): | ||
return [[0, 0, 0]] | ||
triplets = set() | ||
for i in range(len(nums) - 2): | ||
seen = set() | ||
for j in range(i + 1, len(nums)): | ||
f = -(nums[i] + nums[j]) | ||
if f in seen: | ||
triplet = [nums[i], nums[j], f] | ||
triplets.add(tuple(sorted(triplet))) | ||
seen.add(nums[j]) | ||
return list(triplets) |
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class Solution: | ||
def climbStairs(self, n: int) -> int: | ||
if n <= 1: | ||
return 1 | ||
dp = [0] * n | ||
dp[0] = 1 | ||
dp[1] = 2 | ||
for i in range(3, n + 1): | ||
dp[i - 1] = dp[i - 2] + dp[i - 3] | ||
return dp[n - 1] |
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. map대신 set을 사용하셔서 문제 풀이 해보시면 어떨까요 :) |
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class Solution: | ||
def containsDuplicate(self, nums) -> bool: | ||
dic = {} | ||
for num in nums: | ||
dic[num] = dic.get(num, 0) + 1 | ||
for v in dic.values(): | ||
if v > 1: | ||
return True | ||
return False |
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from typing import List | ||
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class Solution: | ||
def rob(self, nums: List[int]) -> int: | ||
if len(nums) <= 1: | ||
return nums[0] | ||
dp = [0] * len(nums) | ||
dp[0], dp[1] = nums[0], max(nums[0], nums[1]) | ||
for i in range(2, len(nums)): | ||
dp[i] = max(dp[i - 1], nums[i] + dp[i - 2]) | ||
return dp[-1] |
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from typing import List | ||
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class Solution: | ||
def longestConsecutive(self, nums: List[int]) -> int: | ||
if len(nums) < 1: | ||
return 0 | ||
nums = list(set(nums)) | ||
nums.sort() | ||
dp = [0] * len(nums) | ||
dp[0] = 1 | ||
for i in range(1, len(nums)): | ||
if nums[i - 1] + 1 == nums[i]: | ||
dp[i] = dp[i - 1] + 1 | ||
else: | ||
dp[i] = 1 | ||
print(dp) | ||
return max(dp) |
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from typing import List | ||
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class Solution: | ||
def productExceptSelf(self, nums: List[int]) -> List[int]: | ||
len_n = len(nums) | ||
front_cum = [1] * len_n | ||
back_cum = [1] * len_n | ||
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for i in range(1, len_n): | ||
front_cum[i] = front_cum[i - 1] * nums[i - 1] | ||
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for j in range(1, len_n): | ||
idx = len_n - j - 1 | ||
back_cum[idx] = back_cum[idx + 1] * nums[idx + 1] | ||
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final = [front_cum[i] * back_cum[i] for i in range(len_n)] | ||
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return final |
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from typing import List | ||
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class Solution: | ||
def topKFrequent(self, nums: List[int], k: int) -> List[int]: | ||
dic = {} | ||
for num in nums: | ||
dic[num] = dic.get(num, 0) + 1 | ||
l = [(k, v) for k, v in dic.items()] | ||
l.sort(reverse=True, key=lambda x: x[1]) | ||
l = [i for i, _ in l] | ||
return l[:k] |
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from typing import List | ||
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class Solution: | ||
def twoSum(self, nums: List[int], target: int) -> List[int]: | ||
nums_dic = {num: idx for idx, num in enumerate(nums)} | ||
for i in range(len(nums)): | ||
remain = target - nums[i] | ||
exists_idx = nums_dic.get(remain) | ||
if exists_idx and exists_idx != i: | ||
return i, exists_idx |
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 시간 복잡도를 O(n) 으로 풀려면 어떻게 하면 될까요 :) |
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class Solution: | ||
def isAnagram(self, s: str, t: str) -> bool: | ||
return sorted(s) == sorted(t) |
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크게 영향은 없지만 if문을 while 문으로 바꿀 수 있을것 같아요 :)