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[chrisjune] WEEK 02 Solutions #1769

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Aug 3, 2025
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17 changes: 17 additions & 0 deletions 3sum/chrisjune.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,17 @@
from typing import List


class Solution:
def threeSum(self, nums: List[int]) -> List[List[int]]:
if len(nums) >= 3 and set(nums) == set([0]):
return [[0, 0, 0]]
triplets = set()
for i in range(len(nums) - 2):
seen = set()
for j in range(i + 1, len(nums)):
f = -(nums[i] + nums[j])
if f in seen:
triplet = [nums[i], nums[j], f]
triplets.add(tuple(sorted(triplet)))
Comment on lines +13 to +15
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크게 영향은 없지만 if문을 while 문으로 바꿀 수 있을것 같아요 :)

seen.add(nums[j])
return list(triplets)
10 changes: 10 additions & 0 deletions climbing-stairs/chrisjune.py
Original file line number Diff line number Diff line change
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class Solution:
def climbStairs(self, n: int) -> int:
if n <= 1:
return 1
dp = [0] * n
dp[0] = 1
dp[1] = 2
for i in range(3, n + 1):
dp[i - 1] = dp[i - 2] + dp[i - 3]
return dp[n - 1]
9 changes: 9 additions & 0 deletions contains-duplicate/chrisjune.py
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map대신 set을 사용하셔서 문제 풀이 해보시면 어떨까요 :)

Original file line number Diff line number Diff line change
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class Solution:
def containsDuplicate(self, nums) -> bool:
dic = {}
for num in nums:
dic[num] = dic.get(num, 0) + 1
for v in dic.values():
if v > 1:
return True
return False
12 changes: 12 additions & 0 deletions house-robber/chrisjune.py
Original file line number Diff line number Diff line change
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from typing import List


class Solution:
def rob(self, nums: List[int]) -> int:
if len(nums) <= 1:
return nums[0]
dp = [0] * len(nums)
dp[0], dp[1] = nums[0], max(nums[0], nums[1])
for i in range(2, len(nums)):
dp[i] = max(dp[i - 1], nums[i] + dp[i - 2])
return dp[-1]
18 changes: 18 additions & 0 deletions longest-consecutive-sequence/chrisjune.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,18 @@
from typing import List


class Solution:
def longestConsecutive(self, nums: List[int]) -> int:
if len(nums) < 1:
return 0
nums = list(set(nums))
nums.sort()
dp = [0] * len(nums)
dp[0] = 1
for i in range(1, len(nums)):
if nums[i - 1] + 1 == nums[i]:
dp[i] = dp[i - 1] + 1
else:
dp[i] = 1
print(dp)
return max(dp)
19 changes: 19 additions & 0 deletions product-of-array-except-self/chrisjune.py
Original file line number Diff line number Diff line change
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from typing import List


class Solution:
def productExceptSelf(self, nums: List[int]) -> List[int]:
len_n = len(nums)
front_cum = [1] * len_n
back_cum = [1] * len_n

for i in range(1, len_n):
front_cum[i] = front_cum[i - 1] * nums[i - 1]

for j in range(1, len_n):
idx = len_n - j - 1
back_cum[idx] = back_cum[idx + 1] * nums[idx + 1]

final = [front_cum[i] * back_cum[i] for i in range(len_n)]

return final
12 changes: 12 additions & 0 deletions top-k-frequent-elements/chrisjune.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,12 @@
from typing import List


class Solution:
def topKFrequent(self, nums: List[int], k: int) -> List[int]:
dic = {}
for num in nums:
dic[num] = dic.get(num, 0) + 1
l = [(k, v) for k, v in dic.items()]
l.sort(reverse=True, key=lambda x: x[1])
l = [i for i, _ in l]
return l[:k]
11 changes: 11 additions & 0 deletions two-sum/chrisjune.py
Original file line number Diff line number Diff line change
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from typing import List


class Solution:
def twoSum(self, nums: List[int], target: int) -> List[int]:
nums_dic = {num: idx for idx, num in enumerate(nums)}
for i in range(len(nums)):
remain = target - nums[i]
exists_idx = nums_dic.get(remain)
if exists_idx and exists_idx != i:
return i, exists_idx
3 changes: 3 additions & 0 deletions valid-anagram/chrisjune.py
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시간 복잡도를 O(n) 으로 풀려면 어떻게 하면 될까요 :)

Original file line number Diff line number Diff line change
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class Solution:
def isAnagram(self, s: str, t: str) -> bool:
return sorted(s) == sorted(t)