[chordpli] WEEK 02 solutions #1776
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feat: 1주차 1,2 문제
* feat: 242 문제 * feat: 70 문제 * feat: leetcode / 15 / success / 투포인터
seungriyou
approved these changes
Aug 3, 2025
| dp[2] = 2 | ||
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| for i in range(3, n + 1): | ||
| dp[i] = dp[i - 1] + dp[i - 2] |
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DP와 예외처리를 이용해서 깔끔하게 풀어주셨네요!
추가로 dp[i]를 계산할 때 dp[i - 1]과 dp[i - 2]만 사용하기 때문에, O(n) space의 리스트가 아닌 O(1) space의 변수 두 개를 이용해서 공간 복잡도를 더 최적화 할 수도 있을 것 같습니다!
| while left < right and nums[left] == nums[left + 1]: | ||
| left += 1 | ||
| while left < right and nums[right] == nums[right - 1]: | ||
| right -= 1 |
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nums를 정렬한 후 투 포인터 이동 시 중복된 원소는 건너뛰는 방식으로 최적화를 하신 것 같네요 🤩
| dic = {} | ||
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| for num in nums: | ||
| if dic.get(num): |
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num이 dic에 존재하는지만 O(1)에 확인하려면 dict()가 아닌 set()을 사용할 수도 있을 것 같아요!
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