[bky373] Week 3 Solutions #75
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climbing-stairs/bky373.java
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배열에 값들을 담아줄 수도 있지만, 현재 값을 구하기 위해서는 전과 전의 전 값만 필요한 것을 고려하면 공간복잡도를 상수항으로 만들 수도 있을 것 같습니다.
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와.. 이런 접근이 가능했군요! 문제 새로 풀어두었습니다 감사합니다!
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져도 처음에는 list에 쌓았는데 피드백 받아서 고쳤습니다ㅎㅎ
DaleSeo
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May 14, 2024
climbing-stairs/bky373.java
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104. Maximum Depth of Binary Tree100. Same Tree572. Subtree of Another Tree70. Climbing Stairs252. Meeting Rooms