[jungsiroo] Week 06 #888
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[jungsiroo] Week 06 #888
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obzva
reviewed
Jan 17, 2025
| from collections import deque | ||
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| """ | ||
| BFS의 아이디어를 차용하여 풀이 |
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풀이와 분석이 깔끔하고 헬퍼함수의 분리가 잘 되어 있는 것 같습니다 :)
이건 간단한 회전변환행렬을 이용한 예전 제 풀이인데, 혹시 관심 있으실까봐 남깁니다
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와 행렬곱은 생각을 못했네요! 감사합니다~
obzva
reviewed
Jan 17, 2025
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+16
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| chars = {'(':1, '{':2, '[':3, ')':-1, '}':-2, ']':-3} | ||
| stack = [] | ||
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| for char in s: | ||
| if chars[char] > 0: | ||
| stack.append(char) |
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이 부분이 좋네요!
value에 정수값을 두니까 조건문이 간단해져서 편해보입니다 :)
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Solving이어서 맘 놓고 있다가 지금 들어왔는데, 벌써 좋은 리뷰가 달렸네요 ^^; |
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@bus710 더 좋은 리뷰를 남겨주시면 되죠~! |
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앞으로 잘 하겠습니다... ㅎㅎ |
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