[Helena] Week 4 solutions #96
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Contributor
yolophg
commented
May 25, 2024
yolophg
commented
- Number of 1 Bits
- Counting Bits
- Reverse Bits
- Missing Number
- Group Anagrams
WhiteHyun
approved these changes
May 26, 2024
| } | ||
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| // convert to unsigned integer. | ||
| return result >>> 0; |
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>>>가 right shift 연산이라면, 0을 해야하는 이유가 있는건지 궁금해요.
이미 result는 양수의 값을 갖고 있으므로 unsigned integer로 만들 것 없이 그냥 반환해도 괜찮지 않을까 생각이 들었거든요.
(JS를 몰라서 제가 예단하고 있는 거겠지만요 ㅎㅎ)
만약 하지 않았을 경우 잘못된 정답이 리턴될 수도 있나요?
nhistory
reviewed
May 26, 2024
| const count = new Array(26).fill(0); | ||
| // increment the count for each character. | ||
| for (const char of str) { | ||
| count[char.charCodeAt(0) - 'a'.charCodeAt(0)]++; |
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ASCII 코드를 활용해서 인덱스 값을 주는 방법도 가능하군요!
좋은 접근방법인 것 같습니다.
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