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Merge pull request #204 from isha0904/VerticalOrderTraversalOfBT
Vertical order traversal of bt
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#include <bits/stdc++.h> | ||
using namespace std; | ||
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int main() | ||
{ | ||
long long a, c = 0; | ||
cin >> a; | ||
int b[a]; | ||
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for (int i; i < a; i++){ | ||
cin >> b[i]; | ||
} | ||
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sort(b, b + a); | ||
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for(int i; i < a; i++){ | ||
c += abs(b[a/2] - b[i]); | ||
} | ||
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cout << c; | ||
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return 0; | ||
} |
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//Solution to Issue #98 -> Vertical Order Traversal of Binary Tree | ||
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class Solution { | ||
public: | ||
vector<vector<int>> verticalTraversal(TreeNode* root) { | ||
// Answer vector to store the vertical traversal results. | ||
vector<vector<int>> ans; | ||
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// Queue to perform a level-order traversal of the binary tree. | ||
queue<pair<TreeNode*, pair<int, int>>> q; | ||
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// Traverse from the root node | ||
q.push({root, {0, 0}}); | ||
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// Map to store nodes based on their column, row, and values. | ||
map<int, map<int, multiset<int>>> mp; | ||
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// Level-order traversal of the binary tree. | ||
while (!q.empty()) { | ||
// Get the front element of the queue. | ||
auto front = q.front(); | ||
q.pop(); | ||
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TreeNode* &node = front.first; | ||
auto &coordinate = front.second; | ||
int &row = coordinate.first; | ||
int &col = coordinate.second; | ||
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// Current node | ||
mp[col][row].insert(node->val); | ||
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// for Left child | ||
if (node->left) | ||
q.push({node->left, {row + 1, col - 1}}); | ||
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// for right child | ||
if (node->right) | ||
q.push({node->right, {row + 1, col + 1}}); | ||
} | ||
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// Map to construct the final result vector. | ||
for (auto it : mp) { | ||
auto &colmap = it.second; | ||
vector<int> vline; | ||
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for (auto mpit : colmap) { | ||
auto &mset = mpit.second; | ||
vline.insert(vline.end(), mset.begin(), mset.end()); | ||
} | ||
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// Adding the values from the current column to the answer vector. | ||
ans.push_back(vline); | ||
} | ||
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// Return the vertical traversal result. | ||
return ans; | ||
} | ||
}; | ||
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/* | ||
By Isha Baviskar ([email protected]) | ||
ID -> isha0904 | ||
*/ |