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Lzw.homework3 #8

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Lzw.homework3 #8

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MinyazevR
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/// <summary>
/// A class representing the bor data structure
/// </summary>
public class Bor

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Он Trie

Comment on lines 28 to 31
public int GetCode()
{
return currentNode.Code;
}

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Suggested change
public int GetCode()
{
return currentNode.Code;
}
public int GetCode()
=> currentNode.Code;

/// <summary>
/// Function to add a byte
/// </summary>
/// <param name="byteToAdd"> byte to add </param>

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Suggested change
/// <param name="byteToAdd"> byte to add </param>
/// <param name="byteToAdd"> Byte to add </param>

Comment on lines 35 to 37
{

string fileName = Path.GetFileNameWithoutExtension(pathToFileToCompress);

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Suggested change
{
string fileName = Path.GetFileNameWithoutExtension(pathToFileToCompress);
{
string fileName = Path.GetFileNameWithoutExtension(pathToFileToCompress);

После открывающей фигурной скобки пустая строка не ставится

using FileStream fs = new(fileName, FileMode.Create);

// Reading all bytes from a file
var stringToConvert = File.ReadAllBytes(pathToFileToCompress);

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Вообще, может быть плохой идеей читать файл в память целиком. Файлы бывают большие. Тем более что LZW может работать побайтово. Но это можно не править, для учебных целей вполне ок.

{
if (args.Length != 2)
{
throw new FileNotFoundException();

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Не, а кто его поймает, если исключение бросается прямо из Main- а? Тут надо вежливо поругаться и рассказать, какие параметры программа ожидает.

if (args[1] == "-u")
{
LZW.DecompressFile(pathToFile);
}

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А если не -c и не -u, то надо что-то сказать пользователю


public class BorTest
{
Bor bor = new();

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Suggested change
Bor bor = new();
private Bor bor = new();

var firstString = File.ReadAllBytes(filename);
var secondString = File.ReadAllBytes("..//..//..//Test");
Assert.AreEqual(firstString, secondString);
}

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На одном файле работает. А на пустом, на текстовом/бинарном?

{

string fileName = Path.GetFileNameWithoutExtension(pathToFileToCompress);
fileName = $"{pathToFileToCompress}..//..//{fileName}.zipped";

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Так мы теряем расширение файла в процессе запаковки/распаковки, что не очень.

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2 participants