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co63oc committed Sep 13, 2023
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50 changes: 0 additions & 50 deletions jointContribution/PIRBN/1D_nonlinear_spring/Cal_jac.py

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34 changes: 0 additions & 34 deletions jointContribution/PIRBN/1D_nonlinear_spring/Dif_op.py

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59 changes: 0 additions & 59 deletions jointContribution/PIRBN/1D_nonlinear_spring/Main.py

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120 changes: 0 additions & 120 deletions jointContribution/PIRBN/1D_nonlinear_spring/OPT.py

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29 changes: 0 additions & 29 deletions jointContribution/PIRBN/1D_nonlinear_spring/PIRBN.py

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39 changes: 3 additions & 36 deletions jointContribution/PIRBN/README.md
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Expand Up @@ -13,44 +13,11 @@ Inspired by findings, we proposed the PIRBN, which can exhibit the local propert

Numerical examples include:

- 1D sine funtion (**Eq. 15** in the manuscript)
- 1D sine funtion (**Eq. 1** in the manuscript)

**PDE**: $\frac{\partial^2 }{\partial x^2}u(x-100)-4\mu^2\pi^2 sin(2\mu\pi(x-100))=0, x\in[100,101]$
**PDE**: $\frac{\partial^2 }{\partial x^2}u(x)-4\mu^2\pi^2 sin(2\mu\pi(x))=0, x\in[0,1]$

**BC**: $u(100)=u(101)=0.$

- 1D sine function coupling problem (**Eq. 30** in the manuscript)

**PDE**: $\frac{\partial^2 }{\partial x^2}u(x)=f(x), x\in[20,22]$

**BC**: $u(20)=u(22)=0.$

- 1D nonlinear spring equation (**Eq. 31** in the manuscript)

**PDE**: $\frac{\partial^2 }{\partial x^2}u(x)+4u(x)+sin[u(x)]=f(x), x\in[0,100]$

**BC**: $u(0)=\frac{\partial }{\partial x}u(0)=0.$

- 2D wave equation (**Eq. 33** in the manuscript)

**PDE**: $(\frac{\partial^2 }{\partial x^2}+4\frac{\partial^2 }{\partial y^2})u(x,y)=0, x\in[0,1], y\in[0,1]$

**BC**: $u(x,0)=u(x,1)=\frac{\partial }{\partial x}u(0,y)=0,$
$u(0,y)=sin(\pi y)+0.5sin(4\pi y).$

- 2D diffusion equation (**Eq. 35** in the manuscript)

**PDE**: $(\frac{\partial}{\partial t}-0.01\frac{\partial^2 }{\partial x^2})u(x,t)=g(x,t), x\in[5,10], y\in[5,10]$

**BC\IC**: $u(5,t)=b_1(t),u(10,t)=b_2(t),u(x,5)=b_3(x).$

- 2D viscoelastic Poiseuille problem (**Eq. 37** in the manuscript)

**PDEs**: $\rho\frac{\partial}{\partial t}u(y,t)=-f+\frac{\partial}{\partial y}\tau_{xy}(y,t), t\in[0,4],$
$\eta_0\frac{\partial}{\partial y}u(y,t)=(\lambda\frac{\partial}{\partial t}+1)\tau_{xy}(y,t), y\in[0,1],$

**BC\IC**: $u(\pm0.5,t)=u(y,0)=0,$
$\tau(y,0)=0.$
**BC**: $u(0)=u(1)=0.$

For more details in terms of mathematical proofs and numerical examples, please refer to our paper.

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