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Merge pull request #143 from SepidehHosseinian/1050.-Actors-and-Direc…
…tors-Who-Cooperated-At-Least-Three-Times 1050.Actors and Directors Who Cooperated
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...ase/Pandas/1050_ActorsandDirectorsWhoCooperatedAtLeastThreeTimes/description.md
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### 1050. Actors and Directors Who Cooperated At Least Three Times | ||
|Easy | ||
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Table: ActorDirector | ||
``` | ||
+-------------+---------+ | ||
| Column Name | Type | | ||
+-------------+---------+ | ||
| actor_id | int | | ||
| director_id | int | | ||
| timestamp | int | | ||
+-------------+---------+ | ||
``` | ||
timestamp is the primary key (column with unique values) for this table. | ||
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Write a solution to find all the pairs (actor_id, director_id) where the actor has cooperated with the director at least three times. | ||
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Return the result table in any order. | ||
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The result format is in the following example. | ||
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Example 1: | ||
``` | ||
Input: | ||
ActorDirector table: | ||
+-------------+-------------+-------------+ | ||
| actor_id | director_id | timestamp | | ||
+-------------+-------------+-------------+ | ||
| 1 | 1 | 0 | | ||
| 1 | 1 | 1 | | ||
| 1 | 1 | 2 | | ||
| 1 | 2 | 3 | | ||
| 1 | 2 | 4 | | ||
| 2 | 1 | 5 | | ||
| 2 | 1 | 6 | | ||
+-------------+-------------+-------------+ | ||
Output: | ||
+-------------+-------------+ | ||
| actor_id | director_id | | ||
+-------------+-------------+ | ||
| 1 | 1 | | ||
+-------------+-------------+ | ||
Explanation: The only pair is (1, 1) where they cooperated exactly 3 times. | ||
``` |
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DataBase/Pandas/1050_ActorsandDirectorsWhoCooperatedAtLeastThreeTimes/solution.py
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import pandas as pd | ||
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def actors_and_directors(actor_director: pd.DataFrame) -> pd.DataFrame: | ||
stats = actor_director.groupby( | ||
['actor_id', 'director_id'], | ||
).agg( | ||
count=('director_id', 'count'), | ||
).reset_index() | ||
return stats[stats['count'] >= 3][['actor_id', 'director_id']] |