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{ | ||
"[python]": { | ||
"editor.defaultFormatter": "ms-python.black-formatter" | ||
}, | ||
"python.formatting.provider": "none" | ||
} |
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Given an array Arr[] of N integers. Find the contiguous sub-array(containing at least one number) which has the maximum sum and return its sum. | ||
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Example 1: | ||
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Input: | ||
N = 5 | ||
Arr[] = {1,2,3,-2,5} | ||
Output: | ||
9 | ||
Explanation: | ||
Max subarray sum is 9 | ||
of elements (1, 2, 3, -2, 5) which | ||
is a contiguous subarray. | ||
Example 2: | ||
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Input: | ||
N = 4 | ||
Arr[] = {-1,-2,-3,-4} | ||
Output: | ||
-1 | ||
Explanation: | ||
Max subarray sum is -1 | ||
of element (-1) | ||
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Your Task: | ||
You don't need to read input or print anything. The task is to complete the function maxSubarraySum() which takes Arr[] and N as input parameters and returns the sum of subarray with maximum sum. | ||
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Expected Time Complexity: O(N) | ||
Expected Auxiliary Space: O(1) | ||
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Constraints: | ||
1 ≤ N ≤ 106 | ||
-107 ≤ A[i] ≤ 107 |
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# User function Template for python3 | ||
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import math | ||
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class Solution: | ||
##Complete this function | ||
# Function to find the sum of contiguous subarray with maximum sum. | ||
def maxSubArraySum(self, arr, N): | ||
max = arr[0] | ||
i = 0 | ||
while i < N: | ||
print("i;", i) | ||
j = i + 1 | ||
per = 1 | ||
while per + j-1 < N: | ||
localMax = 0 | ||
marj = j | ||
it = per | ||
while it > 0 and marj < N: | ||
print("mars:", marj, arr[marj]) | ||
localMax += arr[marj] | ||
marj += 1 | ||
it -= 1 | ||
if localMax > max: | ||
max = localMax | ||
print("max", max) | ||
per += 1 | ||
print("next:", per,i,j, max) | ||
i += 1 | ||
return max | ||
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def main(): | ||
N = 5 | ||
# N = 9 | ||
Arr = [1, 2, 3, -2, 5] | ||
# Arr = [-2, 1, -3, 4, -1, 2, 1, -5, 4] | ||
ob = Solution() | ||
print(ob.maxSubArraySum(Arr, N)) | ||
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if __name__ == "__main__": | ||
main() |
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Given an array of size N-1 such that it only contains distinct integers in the range of 1 to N. Find the missing element. | ||
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Example 1: | ||
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Input: | ||
N = 5 | ||
A[] = {1,2,3,5} | ||
Output: 4 | ||
Example 2: | ||
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Input: | ||
N = 10 | ||
A[] = {6,1,2,8,3,4,7,10,5} | ||
Output: 9 | ||
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Your Task : | ||
You don't need to read input or print anything. Complete the function MissingNumber() that takes array and N as input parameters and returns the value of the missing number. | ||
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Expected Time Complexity: O(N) | ||
Expected Auxiliary Space: O(1) | ||
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Constraints: | ||
1 ≤ N ≤ 106 | ||
1 ≤ A[i] ≤ 106 |
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#User function Template for python3 | ||
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class Solution: | ||
def missingNumber(self,array,n): | ||
# code here | ||
if n==2 and array[0]==1: | ||
return 2 | ||
if n==2 and array[0]==2: | ||
return 1 | ||
array.sort() | ||
i=0 | ||
while i<n-1: | ||
if array[i]!=i+1: | ||
return i+1 | ||
i+=1 | ||
return n | ||
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#{ | ||
# Driver Code Starts | ||
#Initial Template for Python 3 | ||
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N = 10 | ||
N = 5 | ||
A = [6,1,2,8,3,4,7,10,5] | ||
A = [1,2,3,4] | ||
s=Solution().missingNumber(A,N) | ||
print(s) | ||
# } Driver Code Ends |