4thSQLLab

4thSQLLab.sql

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+-- Use the Sakila database
+USE sakila;
+
+-- 1. Determine the number of copies of the film "Hunchback Impossible" in the inventory
+SELECT COUNT(*) AS film_copies FROM inventory 
+WHERE film_id = (SELECT film_id FROM film WHERE title = 'Hunchback Impossible');
+
+-- 2. List all films whose length is longer than the average length of all films
+SELECT title, length FROM film 
+WHERE length > (SELECT AVG(length) FROM film);
+
+-- 3. Display all actors who appear in the film "Alone Trip"
+SELECT actor_id, first_name, last_name FROM actor
+WHERE actor_id IN (
+    SELECT actor_id FROM film_actor
+    WHERE film_id = (SELECT film_id FROM film WHERE title = 'Alone Trip')
+);
+
+-- Bonus
+-- 4. Identify all movies categorized as family films
+SELECT title FROM film
+WHERE film_id IN (
+    SELECT film_id FROM film_category
+    WHERE category_id = (SELECT category_id FROM category WHERE name = 'Family')
+);
+
+-- 5. Retrieve the name and email of customers from Canada using both subqueries and joins
+-- Using subquery
+SELECT first_name, last_name, email FROM customer
+WHERE address_id IN (
+    SELECT address_id FROM address
+    WHERE city_id IN (
+        SELECT city_id FROM city
+        WHERE country_id = (SELECT country_id FROM country WHERE country = 'Canada')
+    )
+);
+
+-- Using JOIN
+SELECT c.first_name, c.last_name, c.email FROM customer c
+JOIN address a ON c.address_id = a.address_id
+JOIN city ci ON a.city_id = ci.city_id
+JOIN country co ON ci.country_id = co.country_id
+WHERE co.country = 'Canada';
+
+-- 6. Determine which films were starred by the most prolific actor
+WITH prolific_actor AS (
+    SELECT actor_id FROM film_actor
+    GROUP BY actor_id
+    ORDER BY COUNT(film_id) DESC
+    LIMIT 1
+)
+SELECT title FROM film
+WHERE film_id IN (
+    SELECT film_id FROM film_actor
+    WHERE actor_id = (SELECT actor_id FROM prolific_actor)
+);
+
+-- 7. Find the films rented by the most profitable customer
+WITH top_customer AS (
+    SELECT customer_id FROM payment
+    GROUP BY customer_id
+    ORDER BY SUM(amount) DESC
+    LIMIT 1
+)
+SELECT f.title FROM rental r
+JOIN inventory i ON r.inventory_id = i.inventory_id
+JOIN film f ON i.film_id = f.film_id
+WHERE r.customer_id = (SELECT customer_id FROM top_customer);
+
+-- 8. Retrieve the client_id and total_amount_spent for clients who spent more than the average amount
+WITH total_spent AS (
+    SELECT customer_id, SUM(amount) AS total_amount FROM payment
+    GROUP BY customer_id
+)
+SELECT customer_id, total_amount FROM total_spent
+WHERE total_amount > (SELECT AVG(total_amount) FROM total_spent);