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Merge pull request #108 from julianhal/random
fessemisk add random chall
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writeups/reversing/Random Flag Generator/FesseMisk/README.md
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# Random Flag Generator | ||
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## Description | ||
This challenge is intened to be an introduction to java. | ||
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`java -jar` to run the program, see if you can find a flag in there somewhere. | ||
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## Solution | ||
I use [JADX](https://github.com/skylot/jadx) to decompile the java code to see what it does. The new ctf meta is of course to use chatgpt to solve the challenge. | ||
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**ME>** | ||
How can i reverse the flag? | ||
```java | ||
import java.util.Base64; | ||
import java.util.Random; | ||
import java.util.Base64.Decoder; | ||
import java.util.Base64.Encoder; | ||
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public class RandomFlagGenerator { | ||
public static void main(String[] var0) { | ||
String var1 = "ATU6Wy9BFBMqCCsXMVQNRT0lRABlGA=="; | ||
String var2 = "Den e brun"; | ||
String var3 = xorString(base64Decode(var1), var2); | ||
String var4 = generateRandomString(20, var3); | ||
System.out.println("Random Flag: " + var4); | ||
} | ||
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public static String generateRandomString(int var0, String var1) { | ||
String var2 = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789abcdefghijklmnopqrstuvwxyz" + var1; | ||
Random var3 = new Random(); | ||
StringBuilder var4 = new StringBuilder(var0); | ||
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for(int var5 = 0; var5 < var0; ++var5) { | ||
var4.append(var2.charAt(var3.nextInt(var2.length()))); | ||
} | ||
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return var4.toString(); | ||
} | ||
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public static String xorString(String var0, String var1) { | ||
StringBuilder var2 = new StringBuilder(); | ||
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for(int var3 = 0; var3 < var0.length(); ++var3) { | ||
var2.append((char)(var0.charAt(var3) ^ var1.charAt(var3 % var1.length()))); | ||
} | ||
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return var2.toString(); | ||
} | ||
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public static String base64Encode(String var0) { | ||
Encoder var1 = Base64.getEncoder(); | ||
return var1.encodeToString(var0.getBytes()); | ||
} | ||
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public static String base64Decode(String var0) { | ||
Decoder var1 = Base64.getDecoder(); | ||
return new String(var1.decode(var0)); | ||
} | ||
} | ||
``` | ||
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**CHATGPT>** | ||
Here’s a Python script that performs the equivalent operations to reveal the flag: | ||
```python | ||
import base64 | ||
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# Step 1: Decode the Base64 string | ||
encoded_string = "ATU6Wy9BFBMqCCsXMVQNRT0lRABlGA==" | ||
decoded_string = base64.b64decode(encoded_string).decode('utf-8') | ||
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# Step 2: XOR the decoded string with "Den e brun" to retrieve the flag | ||
xor_key = "Den e brun" | ||
flag = ''.join(chr(ord(decoded_string[i]) ^ ord(xor_key[i % len(xor_key)])) for i in range(len(decoded_string))) | ||
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print("Original Flag:", flag) | ||
``` | ||
Which when run gives the flag: | ||
`Original Flag: EPT{Java_for_the_W1n!}` |