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#include <iostream> | ||
using namespace std; | ||
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void printEgyptian(int nr, int dr) | ||
{ | ||
// If either numerator or denominator is 0 | ||
if (dr == 0 || nr == 0) | ||
return; | ||
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// If numerator divides denominator, then simple division | ||
// makes the fraction in 1/n form | ||
if (dr%nr == 0) | ||
{ | ||
cout << "1/" << dr/nr; | ||
return; | ||
} | ||
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// If denominator divides numerator, then the given number | ||
// is not fraction | ||
if (nr%dr == 0) | ||
{ | ||
cout << nr/dr; | ||
return; | ||
} | ||
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// If numerator is more than denominator | ||
if (nr > dr) | ||
{ | ||
cout << nr/dr << " + "; | ||
printEgyptian(nr%dr, dr); | ||
return; | ||
} | ||
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// We reach here dr > nr and dr%nr is non-zero | ||
// Find ceiling of dr/nr and print it as first | ||
// fraction | ||
int n = dr/nr + 1; | ||
cout << "1/" << n << " + "; | ||
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// Recur for remaining part | ||
printEgyptian(nr*n-dr, dr*n); | ||
} | ||
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// Driver Program | ||
int main() | ||
{ | ||
int nr = 6, dr = 14; | ||
cout << "Egyptian Fraction Representation of " | ||
<< nr << "/" << dr << " is\n "; | ||
printEgyptian(nr, dr); | ||
return 0; | ||
} |
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