[lab-sql-9] Mickael

lab-sql-9.sql

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+-- In this lab we will find the customers who were active in consecutive months of May and June. Follow the steps to complete the analysis.
+-- Create a table rentals_may to store the data from rental table with information for the month of May.
+
+--
+
+select *, convert(rental_date,date) as month
+from sakila.rental
+;
+-- creating a table with only  the month of may 
+CREATE TABLE rentals_may AS
+-- Insert values in the table rentals_may using the table rental, filtering values only for the month of May.
+select * ,
+date_format(convert(rental_date ,date),'%M') as month
+from sakila.rental
+having month = 'May';
+
+-- viewing the table for May
+
+select *
+from sakila.rentals_may;
+
+-- Create a table rentals_june to store the data from rental table with information for the month of June.
+CREATE TABLE rentals_june AS
+-- Insert values in the table rentals_june using the table rental, filtering values only for the month of June.
+select * ,
+date_format(convert(rental_date ,date),'%M') as month
+from sakila.rental
+having month = 'June';
+
+-- viewing the table for June 
+select *
+from sakila.rentals_june;
+
+-- Check the number of rentals for each customer for May.
+-- looking to table customer 
+select *
+from sakila.customer;
+
+-- Use Join with customer ID, and groupby customer, to get rental of each customer fro MAy
+SELECT c.customer_id, count(r.rental_id) as rental_cust
+FROM sakila.customer c
+LEFT JOIN sakila.rentals_May r ON c.customer_id = r.customer_id
+GROUP BY c.customer_id ;
+
+
+-- Now same thing for the month of June
+SELECT c.customer_id, count(r.rental_id) as rental_cust
+FROM sakila.customer c
+LEFT JOIN sakila.rentals_june r ON c.customer_id = r.customer_id
+GROUP BY c.customer_id ;