disruption: print request/response details to stdout when request fails

pkg/disruption/backend/sampler/producer_consumer.go

@@ -3,6 +3,7 @@ package sampler
 import (
 	"context"
 	"fmt"
+	"os"
 
 	"github.com/openshift/origin/pkg/disruption/backend"
 	"github.com/openshift/origin/pkg/disruption/sampler"
@@ -57,6 +58,21 @@ func (pc *producerConsumer) Produce(stop context.Context, sampleID uint64) (inte
 
 	resp, err := pc.client.Do(req)
 	if err != nil {
+		fmt.Fprintln(os.Stdout, "---")
+		fmt.Fprintf(os.Stdout, "Request URL: %s\n", req.URL)
+		fmt.Fprintf(os.Stdout, "Request Host: %s\n", req.Host)
+		fmt.Fprintln(os.Stdout, "Request Headers:")
+		for k, v := range req.Header {
+			fmt.Fprintf(os.Stdout, "  %s: %v\n", k, v)
+		}
+		fmt.Fprintf(os.Stdout, "Response status: %s\n", resp.Status)
+		fmt.Fprintln(os.Stdout, "Response Headers:")
+		for k, v := range resp.Header {
+			fmt.Fprintf(os.Stdout, "  %s: %v\n", k, v)
+		}
+		fmt.Fprintf(os.Stdout, "Response body: %d\n", resp.Body)
+		fmt.Fprintln(os.Stdout, "---")
+
 		return rr, pc.checker.CheckError(err)
 	}
 	rr.Response = resp