fix(lex): parse let f = (): RT<T>=>null;
#1175
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vegerot
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Jan 10, 2024
| @@ -996,7 +996,12 @@ void Lexer::skip_less_less_as_less() { | |||
| void Lexer::skip_as_greater() { | |||
| switch (this->last_token_.type) { | |||
| case Token_Type::greater_equal: | |||
| this->last_token_.type = Token_Type::equal; | |||
| if (this->input_[0] == '>') { | |||
| this->last_token_.type = Token_Type::equal_greater; | |||
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Must fix: The => token's .end is incorrect after this change. The following example demonstrates the bug:
class C<T> {
f(): C<T>=> {
}
}There was a problem hiding this comment.
Fixed. What do you think?
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Test Plan: `let f = (): RT<T>=>null;` Fixes quick-lint#1169
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fix(lex): parse
let f = (): RT<T>=>null;Test Plan:
let f = (): RT<T>=>null;Fixes #1169