SOAP is dead - long live SOAP

WARNING! First of all this is a fork of the original package.

It made in hope to adapt it for an immediate need for a working SOAP client.

I made some changes to get it work with the specific SOAP-server so there are no guarantees that it will be suitable for anything else.

You have been warned.

First of all do not write SOAP services if you can avoid it! It is over.

If you can not avoid it this package might help.

Service

package main

import (
	"encoding/xml"
	"fmt"
	"net/http"

	"github.com/foomo/soap"
)

// FooRequest a simple request
type FooRequest struct {
	XMLName xml.Name `xml:"fooRequest"`
	Foo     string
}

// FooResponse a simple response
type FooResponse struct {
	Bar string
}

// RunServer run a little demo server
func RunServer() {
	soapServer := soap.NewServer()
	soapServer.HandleOperation(
		// SOAPAction
		"operationFoo",
		// tagname of soap body content
		"fooRequest",
		// RequestFactoryFunc - give the server sth. to unmarshal the request into
		func() interface{} {
			return &FooRequest{}
		},
		// OperationHandlerFunc - do something
		func(request interface{}, w http.ResponseWriter, httpRequest *http.Request) (response interface{}, err error) {
			fooRequest := request.(*FooRequest)
			fooResponse := &FooResponse{
				Bar: "Hello " + fooRequest.Foo,
			}
			response = fooResponse
			return
		},
	)
	err := soapServer.ListenAndServe(":8080")
	fmt.Println("exiting with error", err)
}

func main() {
	RunServer()
}

Client

package main

import (
	"encoding/xml"
	"log"

	"github.com/foomo/soap"
)

// FooRequest a simple request
type FooRequest struct {
	XMLName xml.Name `xml:"fooRequest"`
	Foo     string
}

// FooResponse a simple response
type FooResponse struct {
	Bar string
}

func main() {
	soap.Verbose = true
	client := soap.NewClient("http://127.0.0.1:8080/", nil, nil)
	response := &FooResponse{}
	httpResponse, err := client.Call("operationFoo", &FooRequest{Foo: "hello i am foo"}, response)
	if err != nil {
		panic(err)
	}
	log.Println(response.Bar, httpResponse.Status)
}