Simple object–relational mapping (ORM) library for C# .NET.
It helps creating model classes to represent the tables of a relational database and access them through objects and generic collections to perform CRUD operations without having to write queries or dealing with table rows and columns names.
-
Add
DatabaseModelizer.dllto project references. -
Add the namespace
DatabaseModelizer:
using DatabaseModelizer;- Create a new
DataAccessorobject using a connection string and choose a provider (Ex: Sql, OleDb, Odbc, ...etc):
DataAccessor dataAccessor = new DataAccessor("connection-string-here", DataProvider.Sql);- Now, let's say you have a sql database with the following table:
👤 persons (🔑 id, full_name, gender, birth_date)
Create a new Person model class for this table as follow:
class Person : Model
{
[Column("id")]
public object Id { get; set; }
[Column("full_name")]
[System.ComponentModel.DisplayName("Full Name")]
public object Name { get; set; }
[Column("gender")]
public object Gender { get; set; }
[Column("birth_date")]
[System.ComponentModel.DisplayName("Birth Date")]
public object BirthDate { get; set; }
}As you see, you must derive from Model class and use the ColumnAttribute to specify the database table column that the class property must map to. You can also take this chance to set the .NET DisplayNameAttribute to give the field a name that will be showed when it is used in a control like DataGridView.
- Create a generic
ModelTableobject for the createdPersonType:
ModelTable<Person> persons = new ModelTable<Person>("persons", dataAccessor);The created persons object represents the 👤 persons table in database and can be used to query the table.
- User
personsobject to perform the CRUD operations:
a. Create:
Person newPerson = new Person()
{
Id = Guid.NewGuid(),
Name = "Nina",
Gender = "F",
BirthDate = DateTime.Now
};
Database.Persons.Create(newPerson);b. Read:
List<Person> allPersons = Database.Persons.Read();
List<Person> personsNamedNina = Database.Persons.Read(p => p.Name == "Nina");
Person nina = personsNamedNina[0];b. Update:
nina.Name = "Maria";
Database.Persons.Update(nina, p => p.Id == nina.Id);b. Delete:
Database.Persons.Delete(p => p.Id == nina.Id);PS: Check the included Sample Client example project.
- Language: C# 4.0
- Framework: .NET Framework 4.0 / WinForms
- IDE: Visual Studio 2010
Licensed under MIT.