Skip to content

Commit

Permalink
fix(pontryagin): haar typo and cleanup
Browse files Browse the repository at this point in the history
Fixes #260
  • Loading branch information
vEnhance committed Dec 25, 2024
1 parent 2fbf92f commit 3b81fbc
Showing 1 changed file with 11 additions and 17 deletions.
28 changes: 11 additions & 17 deletions tex/measure/pontryagin.tex
Original file line number Diff line number Diff line change
Expand Up @@ -52,18 +52,15 @@ \section{LCA groups}
\begin{theorem}
[Haar measure]
Let $G$ be a locally compact abelian group.
We regard it as a measurable space
using its Borel $\sigma$-algebra $\SB(G)$.
There exists a measure $\mu \colon \SB(G) \to [0,\infty]$,
called the \vocab{Haar measure},
We regard it as a measurable space using its Borel $\sigma$-algebra $\SB(G)$.
There exists a measure $\mu \colon \SB(G) \to [0,\infty]$, called the \vocab{Haar measure},
satisfying the following properties:
\begin{itemize}
\ii $\mu(gS) = \mu(S)$ for every $g \in G$ and measurable $S$.
That means that $\mu$ is ``translation-invariant''
under translation by $G$.
That means that $\mu$ is ``translation-invariant'' under translation by $G$.
\ii $\mu(K)$ is finite for any compact set $K$.
\ii if $S$ is measurable, then $\mu(S) = \inf\left\{ \mu(U) \mid U \supseteq S \text{ open} \right\}$.
\ii if $U$ is open, then $\mu(U) = \sup\left\{ \mu(S) \mid S \supseteq U \text{ measurable} \right\}$.
\ii if $U$ is open, then $\mu(U) = \sup\left\{ \mu(K) \mid K \subseteq U \text{ compact} \right\}$.
\end{itemize}
Moreover, it is unique up to scaling by a positive constant.
\end{theorem}
Expand All @@ -77,11 +74,9 @@ \section{LCA groups}
For this chapter, we will only use the first two properties at all,
and the other two are just mentioned for completeness.
Note that this actually generalizes the chapter where
we constructed a measure on $\SB(\RR^n)$,
since $\RR^n$ is an LCA group!
we constructed a measure on $\SB(\RR^n)$, since $\RR^n$ is an LCA group!

So, in short: if we have an LCA group,
we have a measure $\mu$ on it.
So, in short: if we have an LCA group, we have a measure $\mu$ on it.

\section{The Pontryagin dual}
Now the key definition is:
Expand All @@ -93,11 +88,10 @@ \section{The Pontryagin dual}
The maps $\xi$ are called \vocab{characters}.
It can be itself made into an LCA group.\footnote{If you must
know the topology, it is the \vocab{compact-open topology}:
for any compact set $K \subseteq G$
and open set $U \subseteq \TT$,
for any compact set $K \subseteq G$ and open set $U \subseteq \TT$,
we declare the set of all $\xi$ with $\xi\im(K) \subseteq U$ to be open,
and then take the smallest topology
containing all such sets. We won't use this at all.}
and then take the smallest topology containing all such sets.
We won't use this at all.}
\end{definition}
\begin{example}
[Examples of Pontryagin duals]
Expand Down Expand Up @@ -231,9 +225,9 @@ \section{Summary}
\text{Fourier series} & \TT \cong [-\pi, \pi] & n \in \ZZ
& \exp(inx) \\ \hline
\text{Continuous Fourier transform} & \RR & \xi \in \RR
& e(\xi x) \\
& e(\xi x) \\
\text{Discrete time Fourier transform} & \ZZ & \xi \in \TT \cong [-\pi, \pi]
& \exp(i \xi n) \\
& \exp(i \xi n) \\
\end{array}
\]
You might notice that the \textbf{various names are awful}.
Expand Down

0 comments on commit 3b81fbc

Please sign in to comment.