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Add proof of Cauchy-Goursat theorem, and various small changes #235
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Great! :)
I think a long time ago I had the impression the proof was difficult. Seeing it written like this confirms I was wrong. So yeah, I think this is an obvious improvement. |
Speaking of which:
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tex/alg-NT/classgrp.tex
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\underbrace{\alpha + \dots + \alpha}_{n\text{ times}} = n\alpha | ||
\pmod \kb \qquad\text{for all } \alpha \in \OO_K. \] | ||
\underbrace{1 + \dots + 1}_{n\text{ times}} = n | ||
\pmod \kb \qquad\text{for } 1 \in \OO_K. \] |
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Actually this change may backfire... after all (n)
is defined to be {n \alpha | \alpha \in \OO_K}
. Guess I'll just revert it.
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\begin{remark} | ||
Note that $\mathcal A$ is a Dedekind domain if and only if $\mathcal A = \OO_K$ for some field | ||
$K$, as we will prove below. We're just defining this term for historical reasons\dots |
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Which feels slightly silly, but I don't see much harm either.
Without defining Dedekind domain, the theorems would read
- 𝒪_K is Noetherian, integrally closed, and "dim Spec 𝒪_K = 1" i.e. prime ideals are maximal.
- ⟹ prime ideal factorization works in 𝒪_K.
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Seems fine.
I think it's supposed to be Omega for simply connected and U if not necessarily simply connected. Any violations of that guideline should be fixed.
I think it's fine to label this section as "Optional". The convention is right now
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I'm obviously just using the book as my lecture note now…
Anyway, I think that saying "works very hard to prove it for the case of a triangle" is a really unfair description of the proof (the key idea is the "binary" (actually quaternary) search. Triangle, rectangle, or circle does not matter --- although it certainly is more difficult to do it in the case of a circle.) (Thinking about it, if you do it on a A4-paper-shaped loop γ, then you can do a binary search.)
And it isn't that difficult.
Plus some minor fixes. (There should be a backslash-space after
\dots
for consistency, but TeX strips trailing spaces anyway, so LaTeX defines backslash-newline to be the same thing as backslash-space.)