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Update README.md
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whydenyscry committed Aug 8, 2024
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Expand Up @@ -157,13 +157,12 @@ $$

then

$$
\Theta = \frac{1}{3}\arccos \mathcal{L} \in \left[0,\dfrac{\pi}{3}\right],
$$

$$
\bar\Theta = \Theta - \frac{\pi}{6} = -\frac{1}{3}\arcsin\mathcal{L} \in \left[-\frac{\pi}{6},\frac{\pi}{6}\right],
$$
```math
\begin{gather}
\Theta = \frac{1}{3}\arccos \mathcal{L} \in \left[0,\dfrac{\pi}{3}\right],\\
\bar\Theta = \Theta - \frac{\pi}{6} = -\frac{1}{3}\arcsin\mathcal{L} \in \left[-\frac{\pi}{6},\frac{\pi}{6}\right],
\end{gather}
```

so principal stresses $\sigma_1,\sigma_2,\sigma_3$

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