[Vidam, Invidam] Week5 Solutions In Go #109
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nhistory
reviewed
Jun 1, 2024
| if sum == 0 { | ||
| triplets = append(triplets, []int{nums[i], nums[j], nums[k]}) | ||
| } | ||
| j, k = update(i, j, k, sum, nums) |
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go 문법 재미있네요! 혹시 이렇게 update 함수를 따로 만들어서 풀이하신 특별한 이유가 있을까요?
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재미있으셨다니 감사합니다 ㅎㅎ..
사실 제가 이전에 C++로 작성한 코드를 슬쩍봤었는데 가시성이 너무 떨어지는 것 같아 분리했었어요
DaleSeo
approved these changes
Jun 2, 2024
| ``` | ||
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| # 여담 | ||
| - 타 솔루션들을 보며 정렬을 하지 않고 빈도수별로 원소들을 모아놨다가 배열을 만드는 방법도 확인했다. 직관적이진 않다고 느꼈다. |
| var max int | ||
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| for _, num := range nums { | ||
| ret := longestConsecutiveFrom(num, appear, cache) |
| ``` | ||
| - - - | ||
| # Intuition | ||
| 솔루션에서 네트워크 통신을 위한다는 목적을 듣고 수정해보았다. (유니코드를 넣는 게 의도는 아닌 듯했다.) |
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5주차 솔루션 올립니다!
솔루션들과는 사뭇 다른 풀이들(
encode-and-decode-strings,product-of-array-except-self)이 있어 신기했습니다